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lyudmila [28]
3 years ago
6

Which of the following statements about sidestream smoke is not true?

Chemistry
1 answer:
Natasha_Volkova [10]3 years ago
3 0

Answer: a

Explanation: the smoker actually exhales the sidestream smoke

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19 – (-11) =<br> Express your answer as an integer.
horsena [70]

Answer:

30

Explanation:

5 0
3 years ago
Read 2 more answers
What elements don't form bonds
Agata [3.3K]

Answer:

Noble gases are a  set of elements in the periodic table because they don't naturally bond with other elements. *Examples ...Helium; Neon; Radon; Xenon; Argon etc

Explanation:

theyre noble gases.

3 0
3 years ago
How many moles of gallium chlorate, Ga(ClO3)3, must react in order to produce 674 kJ of energy according to the following reacti
Valentin [98]

Answer:

10.3 mol Ga(ClO₃)₃

Explanation:

Let's consider the following balanced thermochemical equation.

2 Ga(ClO₃)₃(s) ⇒ 2 GaCl₃(s) + 9 O₂(s)  ΔH = - 130.4 kJ

According to the balanced thermochemical equation, 130.4 kJ of heat are released when 2 moles of gallium chlorate react. The number of moles of gallium chlorate that must react to produce 674 kJ of energy is:

674 kJ × 2 mol Ga(ClO₃)₃/130.4 kJ = 10.3 mol Ga(ClO₃)₃

7 0
3 years ago
An insoluble solid that forms from a chemical reaction is called a(n) _____.
serious [3.7K]
I believe that an insoluble solid that forms a chemical reaction is called a precipitate. 
Precipitate is an insoluble solid that forms when two ionic compounds in solution are combined. Which means precipitation reaction is the creation of a solid from a solution, and when the reaction occurs in a liquid solution, the solid formed is called the precipitate. In fact the only method of forming insoluble salts is called precipitation or double decomposition of salts.
4 0
3 years ago
If a solution containing 117.63 g of silver chlorate is allowed to react completely with a solution containing 10.23 g of lithiu
GuDViN [60]

Answer:

18.8 g

Explanation:

The equation of the reaction is;

AgClO3(aq) + LiBr(aq)------>LiClO3(aq) + AgBr(s)

Number of moles of AgClO3 = 117.63 g/191.32 g/mol = 0.6 moles

Number of moles of LiBr = 10.23 g/86.845 g/mol  = 0.1 moles

Since the molar ratio is 1:1, LiBr is the limiting reactant

Molar mass of solid AgBr = 187.77 g/mol

Mass of precipitate formed = 0.1 moles * 187.77 g/mol

Mass of precipitate formed = 18.8 g

8 0
3 years ago
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