<span>Y = 2x + 4
16x + 4y = 40
substitute </span>Y = 2x + 4 into <span>16x + 4y = 40
</span><span>16x + 4y = 40
</span>16x + 4(2x + 4) = 40
16x + 8x + 16 = 40
24x = 40 - 16
24x = 24
x = 1
Y = 2x + 4
Y = 2(1) + 4
Y = 6
answer (1, 6)
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
Answer:
basicaly your asking to be fulled so {{64
Step-by-step explanation:
Answer:
False
Step-by-step explanation:
20, 25, and 30 no hagas un triángulo rectángulo
The answer is letter c, also just a tip, all i had to do was ask siri :)
