Answer:
where is the picture?
Step-by-step explanation:
To determine what the value of X is simply use the appropriate trigonometric ratio, which in this case is cos.
Cos 21 = 3/X
X • cos 21 = 3
X = 3/(cos 21)
X = 3.123 about 3.1
The value of X to the nearest tenth would be about 3.1.
Answer:
Rewrite as an equation.
log
9(729)=x
Rewrite
log
9(729)=x
in exponential form using the definition of a logarithm. If
x and b
are positive real numbers and b
does not equal 1, then log b(x)=y is equivalent to by=x. 9x=729
Create expressions in the equation that all have equal bases.
(32)x=3
Rewrite
(32)x as 32x. 32x=36
Since the bases are the same, then two expressions are only equal if the exponents are also equal.
2 x 3=6
Solve for
x.x=3
The variable x
is equal to
3.3
Step-by-step explanation:
![\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}](https://tex.z-dn.net/?f=%5Chuge%5Cunderline%7B%5Cred%7BA%7D%5Cblue%7Bn%7D%5Cpink%7Bs%7D%5Cpurple%7Bw%7D%5Corange%7Be%7D%5Cgreen%7Br%7D%20-%7D)
![\tan(\theta) = \frac{perpendicular}{base} \\](https://tex.z-dn.net/?f=%20%5Ctan%28%5Ctheta%29%20%20%3D%20%20%5Cfrac%7Bperpendicular%7D%7Bbase%7D%20%20%5C%5C%20)
we can see we aren't provided with the perpendicular , so let's find it using Pythagoras Theorem !
![H {}^{2} = P {}^{2} + B {}^{2} \\ \\ \dashrightarrow 17 {}^{2} = P {}^{2} + 8 {}^{2} \\ \\ \dashrightarrow \: P {}^{2} = 17 {}^{2} - 8 {}^{2} \\ \\ \dashrightarrow \: P {}^{2} = 289 - 64 \\ \\ \dashrightarrow \: P { }^{2} = 225 \\ \\ \dashrightarrow \: P = \sqrt{225} \\ \\ \dashrightarrow \: P = 15](https://tex.z-dn.net/?f=H%20%7B%7D%5E%7B2%7D%20%20%3D%20P%20%7B%7D%5E%7B2%7D%20%20%2B%20B%20%7B%7D%5E%7B2%7D%20%5C%5C%20%20%5C%5C%20%5Cdashrightarrow%2017%20%7B%7D%5E%7B2%7D%20%20%3D%20P%20%7B%7D%5E%7B2%7D%20%20%2B%208%20%7B%7D%5E%7B2%7D%20%20%5C%5C%20%20%5C%5C%20%5Cdashrightarrow%20%5C%3A%20P%20%7B%7D%5E%7B2%7D%20%20%3D%2017%20%7B%7D%5E%7B2%7D%20%20-%208%20%7B%7D%5E%7B2%7D%20%20%5C%5C%20%20%5C%5C%20%5Cdashrightarrow%20%5C%3A%20P%20%7B%7D%5E%7B2%7D%20%20%3D%20289%20-%2064%20%5C%5C%20%20%5C%5C%20%5Cdashrightarrow%20%5C%3A%20P%20%7B%20%7D%5E%7B2%7D%20%20%3D%20225%20%5C%5C%20%20%5C%5C%20%5Cdashrightarrow%20%5C%3A%20P%20%3D%20%20%5Csqrt%7B225%7D%20%20%5C%5C%20%20%5C%5C%20%5Cdashrightarrow%20%5C%3A%20P%20%3D%2015)
<u>substituting</u><u> </u><u>the </u><u>value </u><u>of </u><u>P </u><u>in </u><u>the </u><u>formula</u>
![\tan(\theta) = \frac{15}{8} \\](https://tex.z-dn.net/?f=%20%20%5Ctan%28%5Ctheta%29%20%20%3D%20%20%5Cfrac%7B15%7D%7B8%7D%20%20%5C%5C%20)
<u>therefore </u><u>,</u><u> </u><u>option </u><u>(</u><u> </u><u>B </u><u>)</u><u> </u><u>is </u><u>correct </u><u>!</u>
hope helpful ~