a = F/(m1+m2)
1.2 = F/48,000
F = 57,600N
a = F/(m1+m3)
a = 57,600/24,000
a = 2.4 m/s^2
Answer:
The magnitude of the acceleration of the 19 kg block is 1.414 m/s²
Explanation:
From Newton's second law of motion;

where;
m is the mass of the objects involved, kg
a is the acceleration of the object, m/s²
different forces on the block and string
⇒force due to 15 kg block
=mgcosθ = 15×9.8×cos20 = 15×9.8×0.9396
= 138.12 N
⇒Tensional Force on 19 kg mass:
T = mg = 19×9.8 = 186.2 N

186.2 - 138.12 = a(15+19)
48.08 = a(34)
a = 48.08/34
a = 1.414 m/s²
Therefore, the magnitude of the acceleration of the 19 kg block is 1.414 m/s²
Explanation:
It is given that,
Radius of curvature of the mirror, R = 1.54 cm
(a) We have to find the focal length of the mirror. The relationship between the focal length and the radius of curvature is given by :

f = focal length of the mirror

f = 0.77 cm
(b) The power of mirror is given by the reciprocal of focal length i.e.
Power, 
P = 1.29 diopters
Hence, this is the required solution.
Answer:
By its amplitude.
Explanation:
loudness is sound intensity & intensity depends on square of amplitude. for example higher the amplitude higher the intensity which means higher the loudness.