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Anna11 [10]
3 years ago
15

Degree day calculations are based on a temperature of?

Physics
1 answer:
Dafna1 [17]3 years ago
5 0

Answer:

65F

Explanation:

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Which scenario involves kinetic energy transforming into potential energy? A. a book lying on a shelf B. a train traveling at a
NeX [460]
The answer is C.

The Kinetic energy which was exerted and experience pulling the string of a bow is kept as a potential energy at the end of the arrow in contact with the string. Once release from aim at stationary position the potential energy is again transformed.
6 0
4 years ago
A motor running at 2600 rev/min is suddenly switched off and decelerates uniformly to rest after 10 s. Find the angular decelera
Mama L [17]
Angular acceleration = (change in angular speed) / (time for the change)

change in angular speed = (zero - 2,600 RPM)  =  -2,600 RPM

time for the change = 10 sec

Angular acceleration = -2600 RPM / 10 sec = -260 rev / min-sec

(-260 rev/min-sec) x (1 min / 60 sec) = <em>-(4 1/3)  rev / sec²</em>

Since the acceleration is negative, the motor is slowing down.
You might call that a 'deceleration' of (4 1/3) rev/sec² .

The average speed is  1/2(2,600 + 0) = 1,300 rev/min = (21 2/3) rev/sec.

Number of revs = (average speed) x (time) = (21 2/3) x (10sec) = <em>(216 2/3) revs</em>
6 0
4 years ago
Which of the following lists the composition of the Earth’s outer core?
iris [78.8K]
Well,

The outer core of the Earth is mostly composed of iron and nickel.

The correct option is C.
5 0
3 years ago
Two forces F1 and F2 of equal magnitude are applied to a brick of mass 20kg lying on the floor as shown in the figure above. If
jeka57 [31]

Let F_{1}=F_{2}=F.

Normal force equals (using Newton's third law) N=mg+F\sin30^{o}-F\sin37^{o}.

F_{f}\leq \mu N = \mu(mg+F\sin30^{o}-F\sin37^{o}), but F_{f}\leq F(\cos30^o+\cos37^o) for all F_{f} (in order to start moving the break). Therefore F(\cos 30^o+\cos37^o)\geq \mu(mg+F\sin30^{o}-F\sin37^{o}), solving for F: F\geq \frac{\mu mg}{\cos30^o+\cos37^o-\mu\sin30^o+\mu\sin37^o}\approx 46,91\; \textbf{N}

7 0
3 years ago
Thought Experiment: A monkey escapes from a zoo and climbs a tree. After failing to entice the monkey down, a zookeeper fires a
Andreyy89

Explanation:

When bullet is shot towards the monkey then let say the distance of monkey from the bullet is "d"

so we can find the time to reach the bullet to the monkey

t = \frac{d}{vcos\theta}

Now similarly we can find the vertical displacement of the bullet in the same time

\Delta y = vsin\theta t - \frac{1}{2}gt^2

\Delta y = v sin\theta (\frac{d}{vcos\theta}) - \frac{1}{2}gt^2

so it is given as

\Delta y = d tan\theta - \frac{1}{2}gt^2

here if the monkey is initially at height H above the ground at given angle then we can say

H = dtan\theta

so we can say that

\Delta y = H - \frac{1}{2}gt^2

So if at the same time monkey will fall down then the height of monkey from ground after time "t" is given as

\Delta y = H - \frac{1}{2}gt^2

so here bullet will hit the monkey as both monkey and bullet are at same position.

3 0
3 years ago
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