Answer:
F = 51.3°
Explanation:
The component of weight parallel to the inclined plane must be responsible for the rolling back motion of the car. Hence, the force required to be applied by the child must also be equal to that component of weight:
where,
W = Weight of Wagon = 150 N
θ = Angle of Inclinition = 20°
Therefore,
<u>F = 51.3°</u>
Answer:
27.5 m/s
Explanation:
applying motion equations we can find the answer,
v = u + a*t
Let assume ,
u = starting speed(velocity)
v = Final speed (velocity)
t = time taken for the motion
a = acceleration
by the time of reaching the highest point subjected to the gravity , the speed should be equal to zero (only a vertical speed component is there)
for the complete motion it takes 5.5 s. that means to reach the highest point it will take 5.5/2 =2.75 seconds
we consider the motion upwards , in this case the gravitational acceleration should be negative in upwards (assume g=10 m/s2)
that is,
v = 0 , a = -10 , t =2.75
v = u + at
0 = u -10*2.75
u = 27.5