What is the motion of the particles in this kind of wave?
2 answers:
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Answer:
a)
b)E=0
c)
Explanation:
Given that
A point charge Q is placed at the center of a conducting spherical shell .Due to this - Q charge will induce on the inner sphere surface and +Q will induce on the outer sphere surface .
a) r < a
At a radius r ,from gauss theorem
b) a < r < b
The total induce in this surface = - Q+ Q =0
E = 0
c) r > b
Answer:
R = 6.67 Ohm's
Explanation:
Resistance is a property of a material that measures the opposition to the flow of current through the material. It is measured in Ohm's.
R = (ρl) ÷ A
where; R is the resistance of the material, A is its cross sectional area, l is its length and ρ is its resistivity.
For the first nichrome wire, resistance is 5 Ohm's.
i.e R = (ρl) ÷ A = 5 Ohm's
For the second nichrome wire, length = 4l, and area of cross section = 3A. The resistance of the second wire can be determined by;
R = (4ρl) ÷ 3A
= {(ρl) ÷ A}
= × 5
R = 6.67 Ohm's
Resistance of the second nichrome wire is 6.67 Ohm's.
We use the formula,
Given, and
.
Substituting these values, we get
.
As Jupiter were a perfect sphere, therefore the volume of sphere is given by
Here, r is the radius of sphere.
Substituting the value of volume we get
.
The diameter is twice of radius, thus the diameter of Jupiter would be