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ElenaW [278]
3 years ago
12

The speed of sound is 330 m/s and the wavelength of a particular sound wave is 33 meters. Calculate the period of this wave.

Physics
2 answers:
weeeeeb [17]3 years ago
8 0
This one is easy it is 11
Anna11 [10]3 years ago
8 0

Answer:

The period of this wave es 10 seconds.

Explanation:

The wavelength is the minimum distance between two points of the wave that is in the same state of vibration.

Frequency is the number of vibrations that occur in a unit of time.

The speed of propagation is the speed with which the wave propagates in the middle. Relate wavelength (λ) and frequency (f) inversely proportionally using the following equation: v = f * λ.

The period is the time that elapses between the emission of two consecutive waves. In other words, it is the time it takes for a complete wave to pass through a reference point. The period (T) is simply the inverse of the frequency (f):

T=\frac{1}{f}

The units of the period are the seconds (s)

Then the propagation speed will be v = λ / T (Speed = wavelength/period)

Then T=  λ / v

Period =  \frac{speed}{wavelength} = \frac{330 \frac{m}{s} }{33 m}

<u><em>Period (T)= 10 s</em></u>

<u><em>The period of this wave es 10 seconds.</em></u>

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Answer:

I = 0.25  AND  T= 4 HOURS, Q = ??  

 multiply  both min  and sec , 240 and 60

we get 1400 sec  

the formula for current is   I = Q/T

substitute the given data in the formula  and simplify it

so , Q = 3600C  

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A mountain slope and a skier make up a closed system with 21,800 J J of energy. When the skier starts her descent down the mount
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What is electronegativity? (2 points)
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the first one

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Answer:

-150 N

Explanation:

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3 years ago
You are designing a ski jump ramp for the next Winter Olympics. You need to calculate the vertical height h from the starting ga
Evgen [1.6K]

Answer:

h = 40.37 m

Explanation:

We will apply the law of conservation of energy to the skier in this case, as follows:

Energy\ of\ skier\ at\ the\ gate = Energy\ of\ Skier\ at\ the\ end\\P.E + K.E_{i} = K.E_{f} - W_{friction}\\mgh + \frac{1}{2}mv_{i}^2 = \frac{1}{2}mv_{f}^2 - W_{friction}\\\\mgh = \frac{1}{2}m(v_{f}^2-v_{i}^2) - W_{friction}

where,

m = mass of skier = 77 kg

g = acceleration due to gravity = 9.81 m/s²

vf = final speed = 30 m/s

vi = initial speed = 2 m/s

W_friction = Work done by friction and air resistance = 4000 J

Therefore,

(77\ kg)(9.81\ m/s^2)h = \frac{1}{2}(77\ kg)[(30\ m/s)^2-(2\ m/s)^2] - 4000\ J\\\\h = \frac{34496\ J - 4000\ J}{755.37\ N}\\\\

<u>h = 40.37 m</u>

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3 years ago
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