Theoretically, if the objects have the same mass and are moving towards each other at a speed of 
, after a perfectly elastic collision, the object A is supposed to move with the same velocity in the opposite direction.
The speed of sound is 330 m/s and the wavelength of a particular sound wave is 33 meters. Calculate the period of this wave.
2 answers:
Answer:
The period of this wave es 10 seconds.
Explanation:
The wavelength is the minimum distance between two points of the wave that is in the same state of vibration.
Frequency is the number of vibrations that occur in a unit of time.
The speed of propagation is the speed with which the wave propagates in the middle. Relate wavelength (λ) and frequency (f) inversely proportionally using the following equation: v = f * λ.
The period is the time that elapses between the emission of two consecutive waves. In other words, it is the time it takes for a complete wave to pass through a reference point. The period (T) is simply the inverse of the frequency (f):
The units of the period are the seconds (s)
Then the propagation speed will be v = λ / T (Speed = wavelength/period)
Then T= λ / v
<u><em>Period (T)= 10 s</em></u>
<u><em>The period of this wave es 10 seconds.</em></u>
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Answer:
(a) Most reactive Metal B
Metal D
Metal A
Least reactive Metal C
(b) (i) Bubbles should form very slowly
(ii) No reaction takes place
Explanation:
(a) The given metals arranged in their order of reactivity are;
Most reactive Metal B
Metal D
Metal A
Least reactive Metal C
The other of reactivity is based on the nature of their reactivity of the metals in air
(b) (i) Based on the reactivity of the metals in air, whereby metal A reacts very slowly and an oxide is formed, we have that, based on the reactivity of the metal A, when mixed with dilute hydrochloric acid, bubbles should form very slowly
(ii) Similarly, given that metal C is unreactive, we have that when small pieces of metal C are added to dilute hydrochloric acid, no reaction takes place.