Question

The speed of sound is 330 m/s and the wavelength of a particular sound wave is 33 meters. Calculate the period of this wave.

Answer 1

This one is easy it is 11

Answer 2

Answer:

The period of this wave es 10 seconds.

Explanation:

The wavelength is the minimum distance between two points of the wave that is in the same state of vibration.

Frequency is the number of vibrations that occur in a unit of time.

The speed of propagation is the speed with which the wave propagates in the middle. Relate wavelength (λ) and frequency (f) inversely proportionally using the following equation: v = f * λ.

The period is the time that elapses between the emission of two consecutive waves. In other words, it is the time it takes for a complete wave to pass through a reference point. The period (T) is simply the inverse of the frequency (f):

$T=\frac{1}{f}$

The units of the period are the seconds (s)

Then the propagation speed will be v = λ / T (Speed = wavelength/period)

Then T=  λ / v

$Period = \frac{speed}{wavelength} = \frac{330 \frac{m}{s} }{33 m}$

Period (T)= 10 s

The period of this wave es 10 seconds.