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Answer:
Infinite amount of solutions
Step-by-step explanation:
Step 1: Write equation
4(3x + 3) = 15x + 7 - 3x + 5
Step 2: Solve for <em>x</em>
- Distribute 4: 12x + 12 = 15x + 7 - 3x + 5
- Combine like terms: 12x + 12 = 12x + 12
- Subtract 12 on both sides: 12x = 12x
- Divide both sides by 12: x = x
Here, we can see that <em>x</em> would be infinite amount of solutions. We can plug in any number <em>x</em> and it would render the equation true.
I'd suggest using "elimination by addition and subtraction" here, altho' there are other approaches (such as matrices, substitution, etc.).
Note that if you add the 3rd equation to the second, the x terms cancel out, and you are left with the system
- y + 3z = -2
y + z = -2
-----------------
4z = -4, so z = -1.
Next, multiply the 3rd equation by 2: You'll get -2x + 2y + 2z = -2.
Add this result to the first equation. The 2x terms will cancel, leaving you with the system
2y + 2z = -2
y + z = 4
This would be a good time to subst. -1 for z. We then get:
-2y - 2 = -2. Then y must be 0. y = 0.
Now subst. -1 for z and 0 for y in any of the original equations.
For example, x - (-1) + 3(0) = -2, so x + 1 = -2, or x = -3.
Then a tentative solution is (-3, -1, 0).
It's very important that you ensure that this satisfies all 3 of the originale quations.
Answer:
11.8%
Step-by-step explanation:
Here in this question, we want to find the probability of no success in the binomial experiment for 6 trials.
Let p = probability of success = 30% = 30/100 = 0.3
q = probability of failure = 1-p = 1-0.3 = 0.7
Now to calculate the probability, we shall need to use the Bernoulli approximation of the binomial theorem.
That would be;
P(X = 0) = 6C0 p^0 q^6
6C0 is pronounced six combination zero
= 6 * 0.3^0 * 0.7^6 = 1 * 1 * 0.117649 = 0.117649
This is approximately 0.1176
If we convert this to percentage we have 11.76%
But we want our answer rounded to the nearest tenth of a percent and that is 11.8%
