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oksian1 [2.3K]
4 years ago
5

Cards. A deck of 52 cards is shuffled and dealt. Find the probabilities of the following events: a) the tenth card is a queen; b

) the twentieth card is a spade; c) the last five cards are spades;
Mathematics
1 answer:
Veronika [31]4 years ago
4 0

Answer:

  • 0.0374
  • 0.0010

Step-by-step explanation:

number of cards = 52

number of queen = 4

number of spades = 13

A) probability that the tenth card is a queen

drawn time (r) = 1

position of success(x) = 10th

p = 4/52

P( x,r,p) = x-1Cr-1*p^(r) * q^(x-r)

p(10,1,4/52) = 9C0(4/52)^1 * (48/52)^9 = 0.0374

B) probability the twentieth card is a spade

x = 20

r = 1

p = 13 / 52

P(20,1,26/52) = 19C0(26/52)^1 * (26/52)^19 = 0.0010

c)  The last five cards been spades

p(last five cards been spades )

p(48..52, 5, 13/52 ) = 47...52C4(13/52)^5 * (39/52)^48..52 - 5

 

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"Four times..." means we're multiplying something by 4.

"... the sum of a number and 15..." means we're adding an unknown and 15 and then multiplying the result by 4.

"... is at least 120" means when we substitute the unknown for a value, in order for that value to be in the solution set, it can only be less than or equal to 120.

So, the resulting inequality is 4(x + 15) ≤ 120.

Simplify the inequality.

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Now that we have the inequality in a simplified form, we can easily see that in order to be in the solution set, the variable x can be no bigger than 15.

In interval notation it would look something like this:

[15, ∞)

In set builder notation it would look something like this:

{x | x ∈ R, x ≤ 15}

It is read as "the set of all x, such that x is a member of the real numbers and x is less than or equal to 15".
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3 years ago
Given f(x)=x3 and g(x)= 1-5x2, fine (fog)(x) and it’s Domain
andre [41]

Answer:

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5 0
3 years ago
Read 2 more answers
WORTH 10 points.
Tanya [424]
The answer is B because I did the math
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