Answer:
See explanation
Step-by-step explanation:
Start by dividing the isosceles triangle in half along the upper vertex angle (not the congruent base angles). This creates two right triangles. Since you divide the triangle in half along an angle, they both have an equal base angle, and they share a side, they are congruent by ASA. Since the corresponding sides of congruent triangles are equal, the sides opposite the congruent base angles of a triangle must be congruent.
Hope this helps!
Answer:
x = 13
Step-by-step explanation:
<em>sqrt (x-4) + 5 = 2</em>
<em>The equation is √(x+4) + 5 = 2</em>
√(x-4) = 2 - 5
√(x-4) = -3
x-4 = (-3)²
x-4 = 9
x = 9 + 4
x = 13
Therefore, the second option x = 13 is correct.
!!
Answer:
6.25 km
Step-by-step explanation:
Here is the correct question: A park is 4 times as long as it is wide. If the distance around the park is 12.5 kilometers, what is the area of the park?
Given: Perimeter (Distance) of the park= 12.5 km
Considering park is in rectangular shape.
Let the width of park be x
∴ as given length will be 4x.
Formula for perimeter of rectangle =
Perimeter is given 12.5 km
⇒ 
⇒ 
∴ x= 1.25 km, which means width is 1.25 km and length is 5 km.
Now, finding the area of park
Formula; Area of rectangle= 
∴ Area of rectangle= 
∴Area of park will be 6.25 km.
Find the perimeter of the rectangle with points...
W(6,9), X(9,7), Y(3,-2), Z(0,0)