Choice A. <span>14/81
</span>Possible outcomes = total number of marbles = 18
P (1st blue) = 8/18 = 4/9
P (2nd red with replacement of blue) = 7/18
P (both) = (4/9) * (7/18) = 28/162 = 14/81
Choice B. 7/18
Possible outcomes = total number of marbles = 18
<span>P (1st black) = 3/18 = 1/6 </span>
<span>P (2nd red with replacement of black) = 7/18 </span>
<span>P (both) = (1/6) * (7/18) = 7/108</span>
1 4 7 I think
I don’t know for sure though
0.037 is the answer unless you divide them in a different order
Answer:
Q1 = 61
Q3 = 63
Step-by-step explanation:
From the plot attached :
Data obtained is :
Temperature frequency
59 0
60 2
61 3
62 3
63 4
64 2
65 1
Frequency Total 15
Data in raw format :
60,60,61,61,61,62,62,62,63,63,63,63,64,64,65
The first quartile :
Q1 = 1/4(n+1)th term
n = 15
Q1 = 1/4(15+1)th term
Q1 = 1/4 * 16th
Q1 = 4th term
Q1 = 61
Third quartile (Q3):
Q3 = 3/4(n+1)th term
n = 15
Q3 = 3/4(15+1)th term
Q3 = 3/4 * 16th
Q3 = (48/4)th term
Q3 = 12th term
Q3 = 63
Answer:
![1-25](https://tex.z-dn.net/?f=1-25)
Step-by-step explanation:
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