He would have $6,760 in his account after year one.
Do 6,500*0.04=260
6,500+260=6,760
Answer:
For less than 7 uniforms.
Step-by-step explanation:
The first company she called charges $70 per uniform.
So, the cost of x uniforms will be $70x.
The second company she called charges $280 plus $30 per uniform.
So, the cost of x uniform will be $(280 + 30x).
Now, if the total cost of purchasing x number of uniforms from the first company is less than that from the second company then, we can write the inequality equation as
70x < 280 + 30x
⇒ 70x - 30x < 280
⇒ 40x < 280
⇒ x < 7
Therefore, for less than 7 uniforms the cost from the first company will be less than the cost from the second company. (Answer)
I need a question or a problem to solve??
Using the formula of P(1 + r)^n = x where p represents the initial value, r represents the rate and n represents the number of years and x is our final output. We want to find P so we have to make it the subject of the equation.
1 + 0.04 = 1.04
1.04^18 = 2.025816515
Then divide the total amount by this to get 185,110.5454
Therefore the answer is $185,110.55
Hope this helps! :)
