He sold 76 shirts and 24 pants.
Step-by-step explanation:
Given,
Cost of one t-shirt = $20
Cost of one pants = $45
Total items sold = 100
Total sales = 2600
Let,
x be the number of t-shirts
y be the number of pants
According to given statement;
x+y=100 Eqn 1
20x+45y=2600 Eqn 2
Multiplying Eqn 1 by 20

Subtracting Eqn 3 from Eqn 2

Dividing both sides by 25

Putting in Eqn 1

He sold 76 shirts and 24 pants.
Keywords: linear equations, subtraction
Learn more about linear equations at:
#LearnwithBrainly
Remark
I think you want us to do both 3 and 4
Three
QR is 4 points going left from the y axis + 2 points going right from the y axis.
QR = 6 units long.
RT is 4 units above the x axis and 3 units below the x axis
RT = 7 units long
TS = 3 units. For this one you just go from T to S. The graph really helps you. You just need to count.
Problem 4
You need to find the area of the combined figure. You could do it as a trapezoid, which might be the easiest way. I'll do that first.
Area = (b1 + b2)*h/2
Givens
B1 = QR = 6
B2 = UT + TS = 6 + 3 = 9
h = RT = 7
Area
Area = (6 + 9)*7/2
Area = 15 * 7 / 2
Area = 52.5
Comment
You could break this up into a rectangle + a triangle
Find the area of QRTU and add the Area of triangle RTS
<em>Area of the rectangle </em>= L * W
L = RT = 7
W = QR = 6
Area = 7 *6 = 42
<em>Area of the triangle</em> = 1/2 * B * H
B = TS = 3
H = RT =7
Area = 1/2 * 3 * 7
Area = 1/2 * 21
Area = 10.5
Total Area = 42 + 10.5 = 52.5 Both answers agree.
Answer:
0.049168726 light-years
Step-by-step explanation:
The apparent brightness of a star is
where
<em>L = luminosity of the star (related to the Sun)
</em>
<em>d = distance in ly (light-years)
</em>
The luminosity of Alpha Centauri A is 1.519 and its distance is 4.37 ly.
Hence the apparent brightness of Alpha Centauri A is
According to the inverse square law for light intensity
where
light intensity at distance
light intensity at distance
Let
be the distance we would have to place the 50-watt bulb, then replacing in the formula
Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.
Answer: can you put a picture
Step-by-step explanation:
Given b equals -3, determine if it is a solution to 4b - 6 = - 18.
So, we have our given which is b = -3, and we are asked to determine if it a solution to the above equation.
To do this, we can plug -3 in for b and see if it works out.
Work:
Plug in -3 for b.
4(-3) - 6 = - 18
-12 - 6 = -18
-12 - 6 = - 18
Thus, b = -3 is a viable solution for the equation of 4b - 6 = -18.