Answer: Answer for figure one is origin (0,0)
Answer for figure two is (2,4) /
Step-by-step explanation:
a) Here we can see that given graph is the equation of cubic function which is
f(-x) = -f(x) that is given function is odd then rotational symmetry point is origin always ,therefore point of rotational symmetry is origin (0,0)
b) The rotational symmetry of an ellipse is 180 degrees about the center of the ellipse .
And here the center of given ellipse is (2,4) ,therefore its rotational symmetry is about (2,4) That is if we rotate the given ellipse 180 degrees about (2,4) it will be at its original position.
Nitrogen (N) has a molar mass of about 14.007 g/mol, so you have
100.0 g N₂ = (100.0 g) • (1/28.014 mol/g) ≈ 3.570 mol N₂
Hydrogen (H) has a molar mass of about 1.008 g/mol, so
100.0 g H₂ = (100.0 g) • (1/2.016 mol/g) ≈ 49.60 mol H₂
In the balanced reaction, 1 mole of N₂ reacts with 3 moles of H₂ to make 2 moles of NH₃. We have
3.570 • 3 ≈ 10.71
so the reaction would use up all 3.570 mol N₂ and 10.71 mol H₂ to produce about 7.139 mol NH₃.
(A) H₂ is the excess reactant. There is an excess of 49.60 - 10.71 ≈ 38.89 mol H₂.
(B) N₂ is the limiting reactant. All of the N₂ gets consumed in the reaction.
(C) NH₃ has a molar mass of (14.007 + 3 • 1.008) g/mol = 17.031 g/mol. This reaction would theoretically yield about 7.139 mol NH₃, or
7.139 mol NH₃ = (7.139 mol) • (17.031 g/mol) ≈ 121.6 g NH₃
Answer:
Option A is correct.
y = 35.4 bushels per acre when rainfall = 7.1 inches
Step-by-step explanation:
An image of the steps to obtain the equation that relates x to y is attached to this answer.
n = number of variables = 9
μₓ = mean of variable x (rainfall in inches)
μᵧ = mean of variable y (yield in bushels per acre)
σₓ = standard deviation of variable x (rainfall in inches)
σᵧ = standard deviation of variable y (yield in bushels per acre)
y = 4.379x + 4.268
when x = 7.1
y = 4.379(7.1) + 4.268 = 35.3589 = 35.4 bushels per acre.
Answer:
The aswer is D
Step-by-step explanation:
The answer is 990 feet I just did the problem
