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ddd [48]
3 years ago
13

How do you find the square root of -24 by simplifying

Mathematics
1 answer:
algol [13]3 years ago
8 0

Answer:

you can't square root with negative numbers the answer will be math error and you cant simplify it unless it has no negative in it.

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What is seven square root two
VLD [36.1K]
7 is the square root or 49 because 7 times Itself would be 49. (7x7=49)
5 0
4 years ago
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. If α and β are the roots of
Lostsunrise [7]

Answer:

18x^2+85x+18 = 0

Step-by-step explanation:

<u><em>Given Equation is </em></u>

=> 2x^2+7x-9=0

Comparing it with ax^2+bx+c = 0, we get

=> a = 2, b = 7 and c = -9

So,

Sum of roots = α+β = -\frac{b}{a}

α+β = -7/2

Product of roots = αβ = c/a

αβ = -9/2

<em>Now, Finding the equation whose roots are:</em>

α/β ,β/α

Sum of Roots = \frac{\alpha }{\beta } + \frac{\beta }{\alpha }

Sum of Roots = \frac{\alpha^2+\beta^2  }{\alpha \beta }

Sum of Roots = \frac{(\alpha+\beta )^2-2\alpha\beta   }{\alpha\beta  }

Sum of roots = (\frac{-7}{2} )^2-2(\frac{-9}{2} ) / \frac{-9}{2}

Sum of roots = \frac{49}{4} + 9 /\frac{-9}{2}

Sum of Roots = \frac{49+36}{4} / \frac{-9}{2}

Sum of roots = \frac{85}{4} * \frac{2}{-9}

Sum of roots = S = -\frac{85}{18}

Product of Roots = \frac{\alpha }{\beta } \frac{\beta }{\alpha }

Product of Roots = P = 1

<u><em>The Quadratic Equation is:</em></u>

=> x^2-Sx+P = 0

=> x^2 - (-\frac{85}{18} )x+1 = 0

=> x^2 + \frac{85}{18}x + 1 = 0

=> 18x^2+85x+18 = 0

This is the required quadratic equation.

5 0
3 years ago
Read 2 more answers
At her job, Jesse. Earn 9 dollars and 50 cents per hour, she also earns a 60 dollar bonus every month. Jesse needs to earn at le
vichka [17]

Answer:

Jesse needs to work 43 hours in the month to make $400 and $60


work for answer: 9.50 x 43 = 408.5

example why it can't be lower or higher than 43 hours 9.50 x 42 = 399  or 9.50 x 44 = 418

7 0
4 years ago
Read 2 more answers
Please anyone answer me
ollegr [7]

Let's divide the shaded region into two areas:

area 1: x = 0 ---> x = 2

ares 2: x = 2 ---> x = 4

In area 1, we need to find the area under g(x) = x and in area 2, we need to find the area between g(x) = x and f(x) = (x - 2)^2. Now let's set up the integrals needed to find the areas.

Area 1:

A\frac{}{1}  = ∫g(x)dx =  ∫xdx =  \frac{1}{2}  {x}^{2}  | \frac{2}{0}  = 2

Area 2:

A\frac{}{2}  = ∫(g(x) - f(x))dx

= ∫(x -  {(x - 2)}^{2} )dx

=  ∫( - {x}^{2}  + 5x - 4)dx

= ( - \frac{1}{3}{x}^{3} +   \frac{5}{2} {x}^{2}  - 4x)   | \frac{4}{2}

= 2.67 - ( - 0.67) = 3.34

Therefore, the area of the shaded portion of the graph is

A = A1 + A2 = 5.34

3 0
3 years ago
A survey of 280 homeless persons showed that 63 were veterans. Construct a 90% confidence interval for the proportion of homeles
MA_775_DIABLO [31]

Answer:

[0.184, 0.266]

Step-by-step explanation:

Given:

Number of survey n =280

Number of veterans = 63

Confidence interval = 90%

Computation:

Probability of veterans = 63/280

Probability of veterans =0.225

a=0.1

Z(0.05) = 1.645 (from distribution table)

Confidence interval = 90%

So,

p ± Z*√[p(1-p)/n]

0.225 ± 1.645√(0.225(1-0.225)/280)

[0.184, 0.266]

4 0
3 years ago
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