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omeli [17]
3 years ago
14

4 Al + 3 O2 -> 2 Al2O3 How much aluminum would be needed to completely react with 45 grams of Oz?

Chemistry
1 answer:
ss7ja [257]3 years ago
6 0

Answer:

50.6g Al would be needed

Explanation:

Based on the reaction:

4Al + 3O₂ → 2Al₂O₃

<em>4 moles of aluminium react with 3 moles of oxygen to produce 2 moles of Al₂O₃</em>

<em />

To solve this question we need to find the moles of 45g of O₂. Then using the chemical equation find the moles of Al and its mass:

<em>Moles O₂ -Molar mass: 32g/mol-:</em>

45g O₂ * (1mol / 32g) = 1.41 moles O₂

<em>Moles Al:</em>

1.41 moles O₂ * (4mol Al / 3mol O₂) = 1.875 moles Al

<em>Mass Al -Molar mass: 26.98g/mol-:</em>

1.875 moles Al * (26.98g / mol) =

50.6g Al would be needed

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Answer:

12.32 L.

Explanation:

The following data were obtained from the question:

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Volume of CH4 =?

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