Answer:
28/95 = 29.,5 % of Arsine decomposed
Explanation:A sample of gaseous arsine (AsH3) in a 460 mL flask at 332 Torr and 223 K, is heated to 437 K, at which temperature arsine decom- poses to solid arsenic and hydrogen gas. The flask is then cooled to 273 K, at which tem- perature the pressure in the flask is 488 Torr. What percentage of arsine molecules have de- composed?
Answer in units of %.
initial pressure 332 Torr initial volume 0.46 L initial temperature 223K
final pressure 488 Torr final volume 0.46 L final 273 K
Torr is 1/760 atm 332 torr = 0.437 atm 488 Torr =0.642 atm
PV = nRT so n=RT/PV
INITIAL n= 0.082 X 223/(0.437)(0.46) = 91 moles
final n= 0.082 X 273 / (.437)(488) = 105 moles
2AsH3----------> 2As + 3H2
x moles of Arsine decomposed to make 1.5 moles of H2
the final number of moles was
(91 -X)+ 1.5 X = 105 moles
91 + 0.5 X = 105
0.5 X = 14
X =28
CHECK
if 28 moles of Arsine , then the container would have
91 --28 + 1.5(28) = 91 +14 =105 check
so 28/95 = 29.,5 % of Arsine decomposed
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