The mass of nitrogen gas that participated in the chemical reaction is 1.54g
HOW TO CALCULATE MASS OF AN ELEMENT:
- Mass of a substance can be calculated by multiplying the number of moles in mol of the substance by its molecular mass in g/mol. That is;
- mass (M) = molar mass (MM) × number of moles (n)
According to this question, a chemist determines by measurements that 0.0550 moles of nitrogen gas (N2) participate in a chemical reaction.
- The molecular mass of nitrogen gas (N2) = 14.01(2)
= 28.02g/mol
Hence, the mass of the nitrogen gas that participated in the chemical reaction is calculated as follows:
- Mass (g) = 0.0550 mol × 28.02 g/mol
Therefore, the mass of nitrogen gas that participated in the chemical reaction is 1.54g
Learn more: brainly.com/question/18269198
Product of this reaction depends on the amount of oxygen.
i.) If oxygen is excess:
Carbon, as graphite, burns to form gaseous carbon (IV) oxide (carbon dioxide), CO2
Equation :
C + O2 ----> CO2. This reaction is also called combustion reaction. The expensive way to produce CO2 is to burn Diamond in the presence of air at 600-800°C. Hope it helped you. :D
Answer:
121 million joules energy is released
Explain :
As there are 500 moles of hydrogen gas in a kilogram, this means that burning a kilogram of hydrogen gas releases 500 times as much energy or 121 million joules .
it is most likely a beaker, beacuse 300ml is quite a large volume. Otherwise, it would be a measuring cylinder or pippette
Answer:
3 significant zeroes
Explanation:
To count the number of significant figures, you must pass the zeroes until you reach a non-zero value. Once you reach it, count anything after that as significant values, including the non-zero value itself.
The number has 4 significant figures with 3 significant zeroes.
Hope this helps!!!
