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3 years ago

Identify the following as either a chemical symbol or a chemical formula. CO Co W Be HI

Chemistry

1 answer:

Nat2105 [25]3 years ago

7 0

Answer:

CO is the chemical formula for carbon monoxide.

Co is the chemical symbol for cobalt.

W is the chemical symbol for tungsten.

Be is the chemical symbol for beryllium.

HI is the chemical formula for hydrogen iodide.

Explanation:

Chemical symbols are either written as a single uppercase letter (ex. O) or an uppercase letter and a lowercase letter (ex. Na).

Chemicals can be anything else! For example CO or even somthing like LiIO.

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How many moles of sulfur trioxide are formed from 3 moles of oxygen using the given

fiasKO [112]

Answer:

6 moles of SO₃ formed.

Explanation:

Given data:

Number of moles of SO₃ formed = ?

Number of moles of oxygen react = 3 mol

Solution:

Chemical equation;

2SO₂+ O₂ → 2SO₃

now we will compare the moles of oxygen and sulfur trioxide.

O₂ : SO₃

1 : 2

3 : 2/1×3 = 6 moles

Thus, six moles of SO₃ will formed.

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3 years ago

1. How many protons does 14/6 C contain? What element is this?

Harman [31]

Answer:

It has 6 protons and its Carbon 14

Explanation:

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3 years ago

How many grams of n2f4 can be produced from 225g f2?

3241004551 [841]

The answer is 615.91 grams of <span>n2f4

Solution:
225g F2 x [(1molF2)/(38gramsF2)] x [</span>(1molF2)/(1molN2F4)] x [(104.02 grams N2F4)/(1molN2F4)]
=615.91 grams

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3 years ago

Why do we use commas after transition words?

ra1l [238]

Answer:

C - commas indicate a natural pause in the sentence

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2 years ago

(06.03 MC) A 50.0 mL sample of gas at 20.0 atm of pressure is compressed to 40.0 atm of pressure at constant temperature. What i

oee [108]

Answer:

New volume is 25.0 mL

Explanation:

Let's assume the gas sample behaves ideally.

According to combined gas law for an ideal gas-

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$

where, $P_{1}$ and $P_{2}$ represent initial and final pressure respectively

$V_{1}$ and $V_{2}$ represent initial and final volume respectively

$T_{1}$ and $T_{2}$ represent initial and final temperature (in kelvin) respectively

Here, $T_{1}=T_{2}$ , $V_{1}=50.0mL$ , $P_{1}=20.0atm$ and $P_{2}=40.0atm$

So, $V_{2}=\frac{P_{1}V_{1}T_{2}}{P_{2}T_{1}}=\frac{(20.0atm)\times (50.0mL)}{40.0mL}=25.0mL$

So, the new volume is 25.0 mL

6 0

3 years ago