Answer is: concentration of hydrogenium ions is 9,54·10⁻⁵ M.
c(HNO₂) = 0,075 M.
c(NaNO₂) = 0,035 M.
Ka(HNO₂) = 4,5·10⁻⁵.
This is buffer solution, so use <span>Henderson–Hasselbalch equation:
pH = pKa + log(c(</span>NaNO₂) ÷ c(HNO₂)).
pH = -log(4,5·10⁻⁵) + log(0,035 M ÷ 0,075 M).
pH = 4,35 - 0,33.
pH = 4,02.
<span>[H</span>₃O⁺] = 10∧(-4,02).
<span>[H</span>₃O⁺] = 0,0000954 M = 9,54·10⁻⁵ M.
Answer:
<em>The correct option here would be the third one because it is true.
</em>
Explanation:
The diagram shows a bar magnet that has lines that are parallel to each other and are pointing towards one side of the rectangle.
The side of rectangle is South Pole because the arrows that are shown in the diagram are nothing but field lines and these lines tend to start from North Pole and the arrow shows moving inside that point hence that point it would be South Pole showing field lines ending at it.
They can be stopped by a piece of paper.
Answer:
1) Has a smaller radius than oxygen because of the increased electromagnetic attraction of the nuclei
2) Has a smaller radius than chlorine because all the electrons of F have lower energy levels and have less repulsion of other electrons and hence are more attracted to the nuclei .
Explanation:
Further the electrons are from the nuclei , the bigger the atomic radius is.
(+) attraction of electrons to the nuclei, (-) repulsion of the electrons away from the nuclei.
1) From O to F:
(+) there is one more proton --> Stronger positive charge of the nuclei means that the electrons are attracted more , then they come closer to it and therefore the radius decreases
(-) There is one more electron --> Every electron is repulsed by others away from the nuclei --> the radius increases. But this effect is not so strong because the new electron is added at the same energy level.
Overall the (+) effect is stronger than the (-) effect --> Radius decreases from O to F
2) From F to Cl
(+) there is one more protons --> Same effect as before
(-) There is one more electron --> Every electron is repulsed by others away from the nuclei. But this time the new electrons have a higher energy level --> Meaning that they are less attracted and hence the radius increases.
And also the other inner layers of electrons (electrons of lower energy levels) repulse this new external layer of electrons more effectively than the case of O --> Strong repulsion effect (called electron shielding effect) --> Radius increases
Overall the (-) effect is stronger than the (+) effect --> Radius increases from F to Cl (or decreases from Cl to F)
