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Alex_Xolod [135]
3 years ago
13

The field lines around one end of a bar magnet are shown below.

Chemistry
2 answers:
bulgar [2K]3 years ago
7 0

Answer:

It is a south pole because the field lines enter the magnet at this end.

Explanation:

jus took the test :)

Vladimir [108]3 years ago
6 0

Answer:

<em>The correct option here would be the third one because it is true. </em>

Explanation:

The diagram shows a bar magnet that has lines that are parallel to each other and are pointing towards one side of the rectangle.

The side of rectangle is South Pole because the arrows that are shown in the diagram are nothing but field lines and these lines tend to start from North Pole and the arrow shows moving inside that point hence that point it would be South Pole showing field lines ending at it.

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Answer: A: Explaining natural events using facts and data AND B:Developing theories using many lines of evidence

Explanation: trust me.

6 0
2 years ago
10 moles of carbon dioxide has a mass of 440 g. What is the relative formula mass of carbon dioxide?
Ksenya-84 [330]

Answer: 44g

Explanation: The formular for finding Moles is ;

Moles =  Mass / Molar Mass or Formular Mass.

Base on this question; Moles = 10, Mass = 440g, and Formular Mass = ?

Making 'Formular Mass', subject of the formular; we thus have;

Formular mass = Mass / Moles = 440/ 10 = 44g

7 0
3 years ago
If the container is closed and the ethanol is allowed to reach equilibrium with its vapor, how many grams of liquid ethanol rema
SVETLANKA909090 [29]

Explanation:

Let us assume that the given data is as follows.

        V = 3.10 L,        T = 19^{o}C = (19 + 273)K = 292 K

       P = 40 torr    (1 atm = 760 torr)

So,     P = \frac{40 torr}{760 torr} \times 1 atm

             = 0.053 atm

          n = ?

According to the ideal gas equation, PV = nRT.

Putting the given values into the above equation to calculate the value of n as follows.

                 PV = nRT

   0.053 atm \times 3.10 L = n \times 0.0821 L atm/mol K \times 292 K

                 0.1643 = n \times 23.97

                    n = 6.85 \times 10^{-3}

It is known that molar mass of ethanol is 46 g/mol. Hence, calculate its mass as follows.

               No. of moles = \frac{mass}{\text{molar mass}}

                 6.85 \times 10^{-3} = \frac{mass}{46 g/mol}  

                    mass = 315.1 \times 10^{-3} g

                              = 0.315 g

Thus, we can conclude that the mass of liquid ethanol is 0.315 g.

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