2 CH₃CH₂CH₃ + 2 Cl₂ → CH₃CH(Cl)CH₃ + CH₃CH₂CH₂Cl + 2 HCl
so according to balanced equation we notice that:
2 mole of propane reacts with 2 moles of Cl₂, so 6 moles of propane will need to react completely with 6 moles Cl₂ (This mean Cl₂ present in excess and propane is the Limiting reagent)
2 mole C₃H₈ gives 2 moles HCl
6 moles C₃H₈ gives ? moles HCl
by cross multiplication we have 6 moles of HCl formed
A= mass number = number of protons and neutrons in the nucleus
Z= number of electrons = number of protons
Given, number of neutrons= 30
Z = A - 30 = 70 - 30 = 40
Z = 40
I hope I was helpful
Answer:
0.744 mol
Explanation:
the balanced equation for the reaction is
8Fe + S₈ ---> 8FeS
molar ratio of Fe to S₈ is 8:1
number of moles of Fe - 55.0 g / 56 g/mol = 0.98 mol
number of moles of S - 23.8 g / 256 g/mol = 0.093 mol
if we are to assume that S₈ is the limiting reactant
if 1 mol of S₈ reacts with 8 mol of Fe
then 0.093 mol of S₈ reacts with - 8 x 0.093 mol = 0.744 mol of Fe
however there's 0.98 mol of Fe present but only 0.744 mol of Fe is needed
therefore Fe is in excess and S₈ is the limiting reagent
molar ratio of S₈ to FeS is 1:8
then 0.093 mol of S₈ reacts with - 8 x 0.093 = 0.744 mol of FeS
number of FeS moles produced is 0.744 mol