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Salsk061 [2.6K]
3 years ago
13

Is the following statement true or false solar panels collect energy from the sun and power a lamp and home Is the following sta

tement true or false solar panels collect energy from the sun can power a lamp in a home
Chemistry
2 answers:
Katen [24]3 years ago
8 0

The following statement is True.

Allisa [31]3 years ago
8 0

Question

<em>Is the following statement true or false solar panels collect energy from the sun and power a lamp and home Is the following statement true or false? Solar panels collect energy from the sun can power a lamp in a home.</em>

Answer:

<em>The following statement is </em><u><em>True</em></u><u>.</u>

Hope this helps!


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Explanation:

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The energy received by Earth from the sun is what type of energy
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Solar Energy

Explanation:

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What are the oxidation numbers of the atoms in this reaction?
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4 years ago
Assume you mix 100.0 mL of 200 M CsOH with 50.0 mL 0f 0.400 M HCl in a coffee cup calorimeter. A reaction occurs. The temperatur
Varvara68 [4.7K]

Answer:

The enthalpy change for the reaction per mole of CsOH is -56.1 kJ/mol

Explanation:

Step 1: Data given

Volume of a CsOH solution = 100.0 mL

Molarity of a CsOH solution = 0.200 M

Volume of HCl solution = 50.0 mL

Molarity of HCl solution = 0.400M

The temperature of both solutions before mixing was 22.50 °C, and it rises to 24.28 °C after the acid-base reaction.

Density = 1.00 g/mL

Specific heat = 4.2 J/gK = 4.2 J/g°C

Step 2: The balanced equation

CsOH + HCl → CsCl + H2O

Step 3: Calculate the energy

Q = m*c*ΔT

⇒with Q = the heat transfer = TO BE DETERMINED

⇒with m = the mass of the solution = (100+ 50 mL) * 1.00 g/mL = 150 grams

⇒with c = the specific heat of the solution = 4.2 J/g°C

⇒with ΔT = The change of temperature = T2 - T1  = 24.28 °C - 22.50 °C = 1.78 °C

Q = 150 grams * 4.2 J/g°C * 1.78 °C

Q = 1121.4 J

Step 4: Calculate moles CsOH

Moles CsOH = molarity CsOH * volume CsOH

Moles CsOH = 0.200M * 0.100 L

Moles CsOH = 0.0200 moles

Step 5: Calculate  the enthalpy change for the reaction per mole of CsOH

ΔH is negative since this is an exothermic reaction

ΔH = -Q/moles

ΔH = -1121.4 J / 0.0200 moles

ΔH = -56070 J/mol = -56.1 kJ/mol

The enthalpy change for the reaction per mole of CsOH is -56.1 kJ/mol

4 0
4 years ago
A 6.68-g aqueous solution of isopropyl alcohol contains 3.97 g of isopropyl alcohol. What is the mass percentage of isopropyl al
Sphinxa [80]

Answer : The mass percentage of isopropyl alcohol in the solution is, 59.4 %

Explanation :

To calculate the mass percentage of isopropyl alcohol in the solution, we use the equation:

\text{Mass percent of isopropyl alcohol}=\frac{\text{Mass of isopropyl alcohol}}{\text{Mass of isopropyl alcohol solution}}\times 100

Mass of isopropyl alcohol = 6.68 g

Mass of isopropyl alcohol solution = 3.97 g

Putting values in above equation, we get:

\text{Mass percent of isopropyl alcohol}=\frac{3.97g}{6.68g}\times 100=59.4\%

Thus, the mass percentage of isopropyl alcohol in the solution is, 59.4 %

6 0
3 years ago
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