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luda_lava [24]
3 years ago
12

Please someone explain me why the answer is not B (4k2m3)?

Mathematics
1 answer:
Zigmanuir [339]3 years ago
4 0

Hi there!

4k^2m^3 is definitely a factor of the the given terms. However, 4 is not the <em>greatest</em> common factor between 8 and 48; it is 8. Therefore, the GCF of the given terms would instead be 8k^2m^3.

I hope this helps!

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tom jogged 3/10 mile, betsy jogged 5/10 mile, and sue jogged 2/10 mile. who jogged a longer distance than 4/10 mile?
Inga [223]
Betsey jogged the longer distance.
5 0
3 years ago
I WILL GIVE BRAINLIEST!!!
zimovet [89]

Not equivalent to any of the given expressions.

Step-by-step explanation:

{7}^{2m} . {6}^{2m}  \\  \\  = (7.6) ^{2m}  \\  \\  =  {42}^{2m}

Hence, {42}^{2m} is not equivalent to any of the given expressions.

6 0
3 years ago
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What is the solution for the equation 3x + 0.3 = 3.3.
hoa [83]

Answer:

3x+0.3=3.3.

                               \            /    

                   We move all terms to the left:

                              3x+0.3-(3.3.)=0

        We add all the numbers together, and all the variables

                              3x+0.3-0=0

        We add all the numbers together, and all the variables

                              3x+0.3=0

     We move all terms containing x to the left, all other terms to the right

                               3x=-0.3

                                x=-0.3/3

                               x=-0.3/3

                               /             \

*eliza*

3 0
3 years ago
Prove that : sinA/1+cosA + 1+cosA/sinA=2cosecA​
tekilochka [14]

Step-by-step explanation:

\frac{sinA}{1+cosA} +\frac{1+cos}{sinA} =2cosec\\\\\\\frac{sin^{2}A+(1+cos)^{2}  }{sinA(1+cosA)} \\\\

\frac{sin^{2}A+1+cos^{2}+2cos}{sinA(1+cosA)} \\\\ and we have sin^{2}+cos^{2} =1

so \frac{1+1+2cosA  }{sinA(1+cosA)} \\\\

\frac{2+2cosA  }{sinA(1+cosA)} \\\\

\frac{2(1+cosA)}{sinA(1+cosA)} \\\\

\frac{2}{sinA} we have \frac{1}{sin}=cosec\\

<em>Finally </em>2cosecA<em />

<em>I really hope this helps coz it took much time </em>

3 0
2 years ago
What is the least common denominator of the fractions 4/15 1/6 and 3/4
Alexus [3.1K]

Answer:

60

Step-by-step explanation:

We have to find least common denominator for these fractions or we just have to find the least common multiple for 15, 6 and 4

In order to find the least common multiple, we have to represent these numbers as factors of prime numbers:

15 = 3 * 5

6 = 2 * 3

4 = 2 * 2

Least common multiples will be common factors (considering that there are no more than of them in other numbers) and the uncommon factors. Then, we can write that:

2 * 2 * 3 * 5 = 60 (there are two 2's, one common 3 and an uncommon 5)

The denominator will be 60 for the least common multiples.

5 0
3 years ago
Read 2 more answers
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