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3 years ago

HELP PLSSS HURRY PLS

Mathematics

1 answer:

nignag [31]3 years ago

6 0

Answer:

Step-by-step explanation:

because it gives us the perimeter, we add all the sides

4z-1+4z-1+5z+3+5z+3=166

8z-2+10z+6=166

18z+4=166

18z=162

z=9

side PS is 5z+3

plug in z to get 45+3=48

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How do you solve 2^5? Explain using academic vocabulary

anastassius [24]

Answer:

well if its 2*5 then its 10 because you have to count by 5's two times and you'll get 10. I hope this helps. :3

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3 years ago

Find cot θ if csc θ = negative square root of thirty seven divided by six and tan θ > 0.

Ket [755]

You can use the trigonometric identity $1+\cot^2{x}=\csc^2{x}$ .

$1+\cot^2{\theta}=(\frac{-\sqrt{37}}{6} )^2 \\ 1+\cot^2{\theta}=\frac{37}{36} \\ \cot^2{\theta}=\frac{1}{36} \\
\cot{\theta}=\frac{1}{6}$

The requirement that $\tan{\theta}\ \textgreater \ 0$ eliminates -1/6 from being another solution.

6 0

2 years ago

The total cost (in hundreds of dollars) to produce x units of a product is c(x) = (3x-2) / (8x+1), find the average cost for eac

olya-2409 [2.1K]

Answer:

a) $\frac{74}{10025}$

b) $\frac{3x-2}{x(8x+1)}$

c) $\frac{-24x^2+32x-2}{(8x^2+x)^2}$

Step-by-step explanation:

For total cost function $c(x)$ , average cost is given by $\frac{c(x)}{x}$ i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., $\left ( \frac{c(x)}{x} \right )'$

Given: $c(x)=\frac{3x-2}{8x+1}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

At x = 50 units,

$\frac{c(50)}{50}=\frac{150-2}{50(400+1)}=\frac{148}{50(401)}=\frac{74}{10025}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

Marginal average cost:

Differentiate average cost with respect to $x$

Take $f=3x-2\,,\,g=8x^2+x$

using quotient rule, $\left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}$

Therefore,

$\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}$

3 0

2 years ago

Sal made 8 ft of sausage links on Friday morning. He used 4 ft for dinner service on Friday night. On Saturday morning, he made

oee [108]

Answer:

Net change in the amount of sausage Sal had from Friday morning until after dinner service Saturday night = 8 - 0 = 8 ft

Step-by-step explanation:

Amount of sausage links made on Friday morning = 8 ft

Amount of sausage links used on Friday night = 4 ft

Amount of sausage links remaining = 8 - 4 = 4ft (i)

Amount of sausage links made on Saturday morning = 8 ft (ii)

So,

Total amount of sausage links = 8 + 4 = 12 ft (from (i) and (ii) )

Amount of sausage links used on Saturday night = 12 ft

Amount of sausage links remaining = 12 - 12 = 0 ft

Net change in the amount of sausage Sal had from Friday morning until after dinner service Saturday night = 8 - 0 = 8 ft

8 0

3 years ago

Please help me with this question!

alisha [4.7K]

Answer:

i think H(5) plus the 50 $ but it may be wrong

Step-by-step explanation:

If H is 60 then 5 times is 300 plus the 50 he already had so it all adds up to 350

8 0

3 years ago