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trapecia [35]
3 years ago
8

Which element was first discovered in space before it was discovered on Earth?

Chemistry
2 answers:
crimeas [40]3 years ago
8 0

Answer:

carbon was discovered in space before on earth

wlad13 [49]3 years ago
7 0

Answer:

carbon

Explanation:

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At constant P and n, T decreases at V is?
goblinko [34]

Answer:

This means that as pressure increases,the volume decreases or the volume increases as the temperature increases, and decreases as the temperature decreases

8 0
3 years ago
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6 0
3 years ago
What is the mole ratio of fe304 to fe?
serg [7]
Answer: 1:3

Explanation:

1) To state the mole ratio of a product and a reactant we need the chemical equation that shows the reaction.

2) In the case of Fe3O4 and Fe, the chemical equation is:

<span>              Fe+H2O → Fe3O4+H2.

3) Now, you balance the equation, which will give you the coefficients of each reactant and product of the chemical reaction:
</span>
<span>              3Fe+4H2O → Fe3O4+4H2

4) From that the mole ratios are:

              3 mol Fe : 4 mol 4H2O : 1 mol Fe3O4 : 4 mol H2.

5) The question requires you to find the mole ratio for Fe3O4 to Fe. Tha is:

            1 mole Fe3O4 : 3 mole Fe

So, the answer is 1:3


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4 0
4 years ago
A reaction of 2.5kg of fissionable material takes place. Assuming a 0.10% mass defect, how much energy is released?
lys-0071 [83]

Answer:

Energy released = 2.25\times 10^{14}\;J

Explanation:

Amount of fissionable material = 2.5 kg

Mass defect = 0.10 % of fissionable material

Mass defect =2.5\times \frac{0.1}{100} = 0.0025\; kg

E = mc^{2}

Where,

m = Mass defect in Kg

C = Speed of light m/s2

C = 3\times 10^{8}\;m/s^2

Now substitute the values in the above equation

E = 0.0025\times (3\times 10^{8})^2 = 2.25\times 10^{14}\;J

5 0
3 years ago
Calculate the expansion work done on the system when exactly 1 mol of solid ammonium chloride, nh4cl, decomposes completely to y
maria [59]

The expansion work on an irreversible system is equal to:

W = - PV

 

Assuming that the gas is ideal, therefore:

PV = nRT

 

[P=pressure, V=volume, n=number of moles, R=gas constant, T=absolute temperature]

 

Therefore,

W = -nRT

W = -(1 mol) * (8.314 J / mol K) * (1250 K)

W = -10,392.50 J

 

Therefore about 10,392.50 J or 10.4 kJ of work is done on the system.

8 0
4 years ago
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