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maksim [4K]
2 years ago
14

Two atoms with an electronegativity difference of 0. 4 form a bond that is.

Chemistry
1 answer:
stepan [7]2 years ago
8 0

Answer:

Nonpolar Covalent

Explanation:

There are 3 main types of bonds: <u>Nonpolar covalent, polar covalent, and ionic</u>. All of them have multiple aspects that set them apart from each other, but in this case, the electronegativity difference is the focus. Electronegativity difference is the difference in the electronegativity values of 2 atoms. For example, Nitrogen has an electronegativity value of 3.04 and Oxygen is 3.44, so their electronegativity difference is 0.4.

Electronegativity values that range from <u>0 to 0.4 are nonpolar covalent, 0.5 to 1.9 is polar covalent, and 2 and above is ionic</u>. Since the difference in this question is 0.4, the bond must be nonpolar covalent.

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When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 14.4 g of carbon were burned in the presence of
Yanka [14]

Answer:

Mass of carbon dioxide produced = 52.8 g

Explanation:

Given data:

Mass of carbon react = 14.4 g

Mass of oxygen = 56.5 g

Mass of oxygen left = 18.1 g

Mass of carbon dioxide produced = ?

Solution:

C + O₂     →      CO₂

Number of moles of C:

Number of moles = mass/ molar mass

Number of moles = 14.4 g/ 12 g/mol

Number of moles = 1.2 mol

18.1 g of oxygen left it means carbon is limiting reactant.

Now we will compare the moles of C with CO₂.

                       C             :         CO₂

                        1             :          1

                      1.2           :          1.2

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 1.2  mol × 44 g/mol

Mass = 52.8 g

8 0
3 years ago
Radium-221 has a half-life of 30 sec. How long will it take for 96% of a sample to decay?
monitta
We can calculate how long the decay by using the half-life equation. It is expressed as:

A = Ao e^-kt

<span>where A is the amount left at t years, Ao is the initial concentration, and k is a constant.
</span><span>From the half-life data, we can calculate for k.
</span>
1/2(Ao) = Ao e^-k(30)
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3 0
3 years ago
If I have an unknown quantity of gas at a pressure of 380 mmHg, a volume of 25 L, and a temperature of
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Answer:

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Explanation:

Data Given:

                Moles  =  n  =  <u>???</u>

                Temperature  =  T  =  300 K

                 Pressure  =  P  =  380 mmHg = 0.50 atm

                 Volume  =  V  =  25 L

Formula Used:

Let's assume that the hydrogen gas in balloon is acting as an Ideal gas, the according to Ideal Gas Equation,

                 P V  =  n R T

where;  R  =  Universal Gas Constant  =  0.082057 atm.L.mol⁻¹.K⁻¹

Solving Equation for n,

                 n  =  P V / RT

Putting Values,

                 n  =  (0.50 atm × 25 L) / (0.082057 atm.L.mol⁻¹.K⁻¹ × 300 K)

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6 0
3 years ago
Given the wavelength of the corresponding emission line, calculate the equivalent radiated energy from n = 4 to n = 2 in both jo
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Explanation:

It is given that,

Initial orbit of electrons, n_i=4

Final orbit of electrons, n_f=2

We need to find energy, wavelength and frequency of the wave.

When atom make transition from one orbit to another, the energy of wave is given by :

E=-13.6(\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2})

Putting all the values we get :

E=-13.6(\dfrac{1}{(4)^2}-\dfrac{1}{(2)^2})\\\\E=2.55\ eV

We know that : 1\ eV=1.6\times 10^{-19}\ J

So,

E=2.55\times 1.6\times 10^{-19}\\\\E=4.08\times 10^{-19}\ J

Energy of wave in terms of frequency is given by :

E=hf

f=\dfrac{E}{h}\\\\f=\dfrac{4.08\times 10^{-19}}{6.63\times 10^{-34}}\\\\f=6.14\times 10^{14}\ Hz

Also, c=f\lambda

\lambda is wavelength

So,

\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{6.14\times 10^{14}}\\\\\lambda=4.88\times 10^{-7}\ m\\\\\lambda=488\ nm

Hence, this is the required solution.

4 0
3 years ago
What molecules can be broken down to one Another ?
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Answer:

compounds can be broken down to one another

4 0
3 years ago
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