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Oxana [17]
3 years ago
9

Which pair of compounds are structural isomers of each other? pentane and 2-methyl pentane pentane and hexane hexane and 2-methy

l pentane 2-methyl hexane and 2-methyl pentane description?

Chemistry
2 answers:
mojhsa [17]3 years ago
6 0
Hexane and 2-methylpentane. If you draw the structures out, you can see that both isomers have 6 carbon atoms and 14 hydrogen atoms. Hence they have the same molecular formula but a different structural formula. I suggest drawing the compounds out for these types of questions to visualise it.
Maurinko [17]3 years ago
6 0

Answer: hexane and 2-methyl pentane

Explanation:

The compounds having similar molecular formula but different arrangement of atoms or groups in space are called isomers and the phenomenon is called as isomerism.

Structural isomers are molecules with the same molecular formula but different arrangements of atoms and thus different structures.

Hexane and 2-methyl pentane have the same number of carbon and hydrogen atoms, so they have same molecular formula of C_6H{14} but their structures are different.

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A chemist wants to find Kc for the following reaction at 751 K: 2NH3(g) + 3 I2 (g) LaTeX: \Longleftrightarrow ⟺ 6HI(g) + N2(g) K
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<u>Answer:</u> The equilibrium constant for the total reaction is 4.09\times 10^{-6}

<u>Explanation:</u>

We are given:

K_{c_1}=0.282\\\\K_{c_2}=41

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<u>Equation 1:</u> N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g);K_{c_1}=0.282

The expression of K_{c_1} for the above equation is:

K_{c_1}=\frac{[NH_3]^2}{[N_2][H_2]^3}

0.282=\frac{[NH_3]^2}{[N_2][H_2]^3}        .......(1)

<u>Equation 2:</u> H_2(g)+I_2(g)\rightleftharpoons 2HI(g);K_{c_2}=41

The expression of K_{c_2} for the above equation is:

K_{c_2}=\frac{[HI]^2}{[H_2][I_2]}

41=\frac{[HI]^2}{[H_2][I_2]}       ......(2)

Cubing both the sides of equation 2, because we need 3 moles of HI in the main expression if equilibrium constant.

(41)^3=\frac{[HI]^6}{[H_2]^3[I_2]^3}

Now, dividing expression 1 by expression 2, we get:

\frac{K_{c_1}}{K_{c_2}}=\left(\frac{\frac{[NH_3]^2}{[N_2][H_2]^3}}{\frac{[HI]^6}{[H_2]^3[l_2]^3}}\right)\\\\\\\frac{0.282}{68921}=\frac{[NH_3]^2[I_2]^3}{[N_2][HI]^6}

\frac{[NH_3]^2[I_2]^3}{[N_2][HI]^6}=4.09\times 10^{-6}

The above expression is the expression for equilibrium constant of the total equation, which is:

2NH_3(g)+3I_2(g)\rightleftharpoons 6HI(g)+N_2;K_c

Hence, the equilibrium constant for the total reaction is 4.09\times 10^{-6}

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