All categories

3 years ago

A new gaming system costs $350. A store offers a 20% discount on the new gaming system. What is the amount of the discount?

Mathematics

2 answers:

Artist 52 [7]3 years ago

5 0

Answer:

Step-by-step explanation:

nexus9112 [7]3 years ago

5 0

Answer: $70

Step-by-step explanation:

1. Make an equation: since 100% price is equal to $350, you can make this ratio => 100:$350=80:$x

x stands for the cost after 20% discount.

2. Solve by cross multiply: 350*80=100x => 28000=100x => x=280

3. Subtract : to find the amount of discount, subtract the discounted price from the original price => 350-280=70

Have a nice day! :D

You might be interested in

A customer pays $18 for DVD that originally cost $20. What is the percent decrease in the cost of the dvd.

Feliz [49]

Answer:

Step-by-step explanation:

18-20=2 so thats your answer

8 0

3 years ago

Please help! 8 and 9/20, will give brainliest. I do not tolerate spam answers! Offering triple points if you answered both!

horsena [70]

Answer:

hi, quick tip

go to cymath or just screenshot the equations or put it in, and it will automatically solve it for you instead of having to wait for someone to answer.

hope this works :}

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Find the value of c that completes the square. k^2-18k+c

eimsori [14]

Answer:

c = 81

(k-9)(k-9)

k²-18k +81

4 0

3 years ago

Read 2 more answers

Look at the attachment.

Sloan [31]

Answer:

12 cups

Step-by-step explanation:

21:7=3 i mean that's kinda it

3x4=12

4 0

3 years ago

The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?

Serhud [2]

Answer:

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

Step-by-step explanation:

Given - The circumference of the ellipse approximated by $C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }$ where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

$C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi } = \sqrt{\frac{a^{2} + b^{2} }{2} }$

Squaring Both sides, we get

$[\frac{C}{2\pi }]^{2} = [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2} } = {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2} } = {{a^{2} + b^{2} }$

$\frac{C^{2} }{2(\pi )^{2} } = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} } - a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}} = b$

∴ we get

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

8 0

3 years ago