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nevsk [136]
3 years ago
7

A man runs at the speed of 10 km/hr. How much time will he take to cover 2000 meters?

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
4 0
200 hours.

It’s 10km for every one hour
Divide 2000 by 10 and you will be left with the number of km for every one hour.
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According to the given information, segment uv is parallel to segment wz, while angles squ and vqt are vertical angles. angle vq
svp [43]

Angle vqt is congruent to Angle squ by the vertical angles theorem. because angles squ and wrs are corresponding angles, they are congruent according to the Corresponding angles theorem.

Option b is true.

Here,

Segment uv is parallel to segment wz,

Angles squ and vqt are vertical angles.

Angle vqt is congruent to Angle squ by the Vertical angles theorem.

What is corresponding angles?

Any pair of angles each of which is on the same side of one of two lines cut by a transversal and on the same side of the transversal.

Now,

Angle vqt is congruent to Angle squ by the vertical angles theorem.

When, two angles are corresponding angle then, Angle vqt is congruent to Angle squ by the Vertical angles theorem.

And, they are congruent according to the Corresponding angles theorem.

Hence, Segment uv is parallel to Segment wz, while Angles squ and vqt are Vertical angles. Angle vqt is congruent to Angle squ by the vertical angles theorem. Because angles squ and wrs are corresponding angles, they are congruent according to the corresponding angle theorem. finally, Angle vqt is congruent to Angle wrs by the transitive property of equality.

So, Option b is true.

Learn more about the corresponding angles visit:

brainly.com/question/22190474

#SPJ4

4 0
2 years ago
What is the answer to <br>|5 + -4|
luda_lava [24]

|a|=\left\{\begin{array}{ccc}a&if&a\geq0\\-a&if&a < 0\end{array}\right\\\\|5+(-4)|=|5-4|=|1|=1

3 0
4 years ago
Compare this: |a| and 0
slavikrds [6]

Answer:

when they are pronounce /a/ does not need any force while /o/ w need more force

3 0
3 years ago
What whole number dimensions would allow the students to maximize the volume while keeping the surface area at most 160 square f
ycow [4]

Answer:

The whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square is 6 ft

Step-by-step explanation:

Here we are required find the size of the sides of a dunk tank (cube with open top) such that the surface area is ≤ 160 ft²

For maximum volume, the side length, s of the cube must all be equal ;

Therefore area of one side = s²

Number of sides in a cube with top open = 5 sides

Area of surface = 5 × s² = 180

Therefore s² = 180/5 = 36

s² = 36

s = √36 = 6 ft

Therefore, the whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square = 6 ft.

6 0
3 years ago
Someone please help??
irga5000 [103]

Answer:

Im not 100% sure but i can tell you it is (D)

Step-by-step explanation:

8 0
3 years ago
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