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Vlada [557]
3 years ago
8

A salesperson works 40 hours per week at a job where she has two options for being paid. Option A is an hourly wage of ​23$. Opt

ion B is a commission rate of ​4% on weekly sales. How much does she need to sell this week to earn the same amount with the two​ options?
Mathematics
2 answers:
Gwar [14]3 years ago
7 0

Step-by-step explanation:

  1. A salesperson works 40 hours per week at a job where she has two options for being paid. Option A is an hourly wage of 23$. Option B is a commission rate of 4% on weekly sales. How much does she need to sell this week to earn the same amount with the two options?
  2. A salesperson works 40 hours per week at a job where she has two options for being paid. Option A is an hourly wage of 23$. Option B is a commission rate of 4% on weekly sales. How much does she need to sell this week to earn the same amount with the two options?
  3. A salesperson works 40 hours per week at a job where she has two options for being paid. Option A is an hourly wage of 23$. Option B is a commission rate of 4% on weekly sales. How much does she need to sell this week to earn the same amount with the two options?
Alja [10]3 years ago
7 0

Answer:

Your answer is

She needs to sell products of 23000$ to earn the same amount

Want more answer then follow me, like and MARK MY ANSWER AS BRAINLIST ANSWER.

I need that urgently.

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Answer:

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Step-by-step explanation:


7 0
3 years ago
Given g(x) = −3x + 4
Goshia [24]

Answer:

The average rate of change of <em>g</em> from <em>x</em> = <em>a</em> to<em> x</em> = <em>a</em> + <em>h</em> is -3.

Step-by-step explanation:

We are given the function:

g(x) = -3x + 4

And we want to determine its average rate of change of the function for <em>x</em> = <em>a</em> and <em>x</em> = <em>a</em> + <em>h</em>.

To determine the average rate of change, we find the slope of the function between the two points. In other words:

\displaystyle \text{Avg} = \frac{g(a + h) - g(a) }{(a + h ) - a}

Simplify:

\displaystyle \begin{aligned}  \text{Avg} &= \frac{g(a + h) - g(a) }{(a + h ) - a} \\ \\ &=\frac{(-3(a+h) + 4) - (-3a+4)}{h} \\ \\ &= \frac{(-3a -3h + 4) + (3a - 4) }{h} \\ \\ &= \frac{-3h}{h} \\ \\ &= -3\end{aligned}

In conclusion, the average rate of change of <em>g</em> from <em>x</em> = <em>a</em> to <em>x</em> = <em>a</em> + <em>h</em> is -3.

This is the expected result, as function <em>g</em> is linear, so its rate of change would be constant.

3 0
3 years ago
What is the arc length of the semicircle
MrMuchimi

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The arc length of the semicircle is half the circumference of the full circle

8 0
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The pressure and volume of an expanding gas are related by the formula PV^b=C, where b and C are constants (this holds in adiaba
bazaltina [42]

The dP/dt of the adiabatic expansion is -42/11 kPa/min

<h3>How to calculate dP/dt in an adiabatic expansion?</h3>

An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression

Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min

PVᵇ = C

Taking logs of both sides gives:

ln P + b ln V = ln C

Taking partial derivatives gives:

\frac{1}{P}\frac{∂P}{∂t}  + \frac{b}{V}\frac{∂V}{∂t} = 0

Substitutituting the values b, P, V and dV/dt into the derivative above:

1/7 x dP/dt +  1.5/110 x 40 = 0

1/7 x dP/dt +  6/11 = 0

1/7 x dP/dt = - 6/11

dP/dt = - 6/11 x 7

dP/dt = -42/11 kPa/min

Therefore, the value of  dP/dt is -42/11 kPa/min

Learn more about adiabatic expansion on:

brainly.com/question/6966596

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4 0
1 year ago
Use the figure below to find the value of y and each angle shown.
igomit [66]

5y - 16 + 3y + 20 = 180 degrees

Combine like terms on the left side

8y + 4 = 180

Subtract 4 from both sides.

8y = 176

Divide both sides by 8

y = 22

Plug 22 into y for each angle.

3y + 20 = 3(22) + 20 = 66 + 20 = 86 degrees

5y - 16 = 5(22) - 16 = 110 - 16 = 94

The angle opposite 5y - 16 also equals 94 because they are vertical angles.

The angle opposite of 3y + 20 also equals 86 because they are vertical angles

6 0
3 years ago
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