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3 years ago

Why is this hard. I'm not a genius. but genius can only solve this problem.

Mathematics

2 answers:

shtirl [24]3 years ago

8 0

Answer:

very easy

Step-by-step explanation:

miss Akunina [59]3 years ago

6 0

Answer:

4 + 4 = 8

+ +

8 - 4 = 6

|| ||

13 8

___________________________

i dont iknow if im right :(

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17. Which of the following measures can be calculated for qualitative data? a. Mean b. Median c. Mode d. All of these

VLD [36.1K]

Answer: C. Mode

Step-by-step explanation:

Qualitative data applies to observable data such as reoccurring patterns (mode)

Quantitative data applies to numbers and numerical calculations (Mean, Median)

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3 years ago

R + s² at r = 4, s = 1 ( Pls show work) AND NO LINKS THX UwU

icang [17]

r+s^2

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4+2

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3 years ago

The quotient of a number and nine

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3 years ago

What is the amplitude of y = 4 cos 3x?<br> oc<br> o timmt

JulijaS [17]

Answer:

The amplitude is 4

Step-by-step explanation:

Recall that the amplitude of a harmonic form like this one based on the cosine function is the absolute value of the coefficient that multiplies the function. In our case that coefficient is 4.

So the amplitude of this function is "4".

4 0

4 years ago

What is AE and the perimeter of BCDE? Round your answer to the nearest tenth.

Oliga [24]

Answer:

AE = 43.2 units

Perimeter = 229.2 units

Step-by-step explanation:

Let the side AE be 'x'.

Consider triangles AEB and ADC

Statements Reasons

1. ∠ ABE ≅ ∠ ACD Right angles are congruent.

2. ∠A ≅ ∠A Common angle

Therefore, the two triangles are similar by AA postulate.

Now, for similar triangles, the ratio of their corresponding sides are also proportional to each other. Therefore,

$\frac{AE}{AD}=\frac{AB}{AC}=\frac{BE}{DC}\\\\\frac{AE}{AE+ED}=\frac{AC-BC}{AC}$

Now, plug in the given values and solve for 'x'. This gives,

$\frac{x}{x+72}=\frac{88-55}{88}\\\\88x=33(x+72)\\\\88x=33x+2376\\\\88x-33x=2376\\\\55x=2376\\\\x=\frac{2376}{55}=43.2$

Therefore, AE = 43.2 units

Now, from right angled triangle ABE,

$(AB)^2+(BE)^2=(AE)^2...(Pythagoras\ Theorem)\\\\(33)^2+(BE)^2=(43.2)^2\\\\BE=\sqrt{(43.2)^2-(33)^2}=27.879$

Similarly from right angled triangle ACD,

$CD=\sqrt{AD^2-AC^2}\\\\CD=\sqrt{(72+43.2)^2-88^2}=74.344$

Now, perimeter is the sum of all the sides of a figure. Therefore, the perimeter of BCDE is given as:

Perimeter = BE + ED + CD + BC

Perimeter = 27.879 + 72 + 74.344 + 55 = 229.223 ≈ 229.2 (Nearest tenth)

Therefore, the perimeter = 229.2 units

6 0

3 years ago