Please help me pleeeeeeaaassseee

Mathematics

1 answer:

mr_godi [17]3 years ago

4 0

Answer:

Step-by-step explanation:

answer no 3:

1] Factor out the common term 2.

2(3x+y) = -26

2] Divide both sides by 2.

3x+y= -26/2

3x+y = − 13

3]Subtract y from both sides.

3x = - 13-y

4] Divide both sides by 3.

x = -13-y/3

Part 2:-

Add 6y to both sides.

x=21+6y

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Indicate in standard form the equation of the line passing through the given point and having the given slope

Naddik [55]

ANSWER

The equation is

$y - 5x + 20 = 0$

EXPLANATION

Let the equation be
$y = mx + c$

where
$m = 5$
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We substitute this value to obtain,

$y = 5x + c$

Since the line passes through
$(4,0)$
we can use this point to determine the value of c.

We substitute this point to obtain,

$0 = 5(4) + c$

$0 = 20 + c$

$c = - 20$

Our equation now becomes

$y = 5x - 20$

We can write this in standard form as

$y - 5x + 20 = 0$

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3 years ago

Find the value of x. x=

Free_Kalibri [48]

Answer: 110

Reasoning: all of the numbers should add up to 360.

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The angles of 110 look the same, go for it.

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3 years ago

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Deffense [45]

If this is for slope-intercept, the equation is: y = 3x + 1

To find the slope, you would find the rise over run ( $\frac{rise}{run}$ ). So, you would start where the graph intersect at the y-axis, which is 1. You would go up 3 times, and right 1 time. So, $\frac{3}{1}$ , or 3, would be your slope. To find the y-intercept, you would need to find where the graph intersects at the y-axis, which is 1, so it would be your y-intercept. Plug them into the y = mx + b formula and the answer is y = 3x + 1.