Answer:
Using the probability mass function we got:
And adding the probabilities we got:
Step-by-step explanation:
Previous concepts
The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".
Let X the random variable of interest, on this case we now that:
The probability mass function for the Binomial distribution is given as:
Where (nCx) means combinatory and it's given by this formula:
Solution to the problem
For a fair coin flip n=28 times we have the following distribution:
We want to find this probability:
Using the probability mass function we got:
And adding the probabilities we got:
Answer:
The probability is 8 over 15.
Step-by-step explanation:
14 of the musicians play both guitar and drums, 28 play drums, 18 play the guitar.
It means n(G and D)=14, n(D)=28, n(G)=18.
Using the formula of Union:-
n(G or D) = n(G) + n(D) - n(G and D).
n(G or D) = 18 + 28 - 14.
n(G or D) = 32.
It says 60 musicians applied for a job at a music school. So n(U)=60.
the probability that the applicant who gets the job plays drums or guitar is = n(G or D)/n(U) = 32/60 = 8/15.
Hence, the probability is 8 over 15.
Answer:
I really don't get your question
Answer:
Question 1: False
Question 2: True
Question 3: True
Question 4: False
Step-by-step explanation:
Peter babysits his sister 2 days: Monday and Friday.
He babysits for his neighbor 40% of the time between Monday through Friday. This includes 5 days. 40% of 5days = 2 days.
On the weekend, Peter babysits 50% of the days. There are 2 days in the weekend
50% × 2 days = 1 day.
Question 1: False
Altogether, Peter babysits 5 days every week.
Question 2: True
Question 3: True
Peter babysits 4 out 5 days during Monday-Friday 4/5= 80%
Question 4: False
Peter babysits 5 days out of 7 during the week. 5/7 = 71% of the days, which is less than 90%