Question

How do you do this question?

Answer 1

Answer:

The required relation is,

  $\frac {dV}{dt}$ = $c{\frac{dT}{dt}}$

Step-by-step explanation:

We know that for a certain amount of dry gas when the pressure is kept constant it's volume V and temperature T is related by the function,

V = cT -----------------------(1) [where "c" is a constant]

So, in that case rate of change of volume(V) with respect to time (t),

             = $\frac {dV}{dt}$

will be equal to ,

               $c{\frac{dT}{dt}}$

where $\frac {dT}{dt}$  is equal to rate of change of temperature (T) with  respect to time (t) and c is the constant stated before.

So, the required relation is,

  $\frac {dV}{dt}$ = $c{\frac{dT}{dt}}$