Answer:
8.45 L
Explanation:
From the question given above, the following data were obtained:
Initial temperature (T₁) = 50 °C
Initial pressure (P₁) = 2 atm
Initial volume (V₁) = 5 L
Final temperature (T₂) = 0 °C
Final pressure (P₂) = 1 atm
Final volume (V₂) =?
Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T₁) = 50 °C
Initial temperature (T₁) = 50 °C + 273
Initial temperature (T₁) = 323 K
Final temperature (T₂) = 0 °C
Final temperature (T₂) = 0 °C + 273
Final temperature (T₂) = 273 K
Finally, we shall determine the new volume. This can be obtained as follow:
Initial temperature (T₁) = 323 K
Initial pressure (P₁) = 2 atm
Initial volume (V₁) = 5 L
Final temperature (T₂) = 273 k
Final pressure (P₂) = 1 atm
Final volume (V₂) =?
P₁V₁ / T₁ = P₂V₂ / T₂
2 × 5 / 323 = 1 × V₂ / 273
10 / 323 = V₂ / 273
Cross multiply
323 × V₂ = 10 × 273
323 × V₂ = 2730
Divide both side by 323
V₂ = 2730 / 323
V₂ = 8.45 L
Thus, the new volume is 8.45 L
