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3 years ago

Calculate the molarity of 29.0g of ethanol (C2H5OH) in 545 mL of solution.

2 answers:

7 0

There are a number of ways to express concentration of a solution. This includes molarity. Molarity is expressed as the number of moles of solute per volume of the solution. Molarity of the solution given is calculated as follows:

M = (29.0 g ethanol) (1 mol / 46.07 g) / 545mL (1L / 1000mL)
M = 1.16 mol / L

BigorU [14]3 years ago

5 0

Molar mass ethanol:

C2H5OH = 12 x 2+ 1 x 5 + 16 + 1 = 46.0 g/mol

volume = 545 mL in liters: 545 / 1000 => 0.545 L

number of moles:

29.0 / 46.0 => 0.6304 moles

M = n / V

M = 0.6304 / 0.545

M = 1.156 mol/L

hope this helps!

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From the question we are told

A solution made by mixing 20.0 g of a non-volatile compound with 125 mL of water at 25°C has a vapor pressure of 22.67 torr. What is the molecular weight (3sf) of the compound (g/mol).

Generally the equation for the Rouault's law is mathematically given as

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