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Licemer1 [7]
2 years ago
8

What are some characteristic properties of elements to the left of the elements along the ""staircase""? To the right?

Chemistry
1 answer:
o-na [289]2 years ago
7 0

Metalloids make up the elements that line the line. Both metallic and nonmetallic qualities can be found in them. More electrons are typically gained than lost by the elements to the line's immediate right.

On the periodic table, the nonmetals are to the right of the stair-step line. In chemical processes, metals frequently lose electrons and produce positive ions.

<h3>What is Periodic Table ? </h3>

The chemical elements are shown in tabular form on the periodic table, sometimes referred to as the periodic table of the elements. It is frequently used in physics, chemistry, and other sciences and is frequently regarded as a symbol of chemistry.

<h3>What are Metalloids?</h3>

The term is usually applied to a group of six to nine elements (boron, silicon, germanium, arsenic, antimony, tellurium, and possibly bismuth, polonium, astatine) near the middle of the P block or main block of the periodic table increase.

  • Metals are typically hard, bright, fusible, malleable, and ductile elements with excellent electrical and thermal conductivity.
  • Non-metals are elements that do not have metallic properties. Metalloids are elements with properties intermediate between those of metals and nonmetals.
  • In some cases, these elements are referred to as semimetals.
  • Examples of metalloids include boron, silicon, tellurium, germanium, arsenic, antimony. Others include aluminum, astatine, polonium, etc.

To know more about Metalloids please click here : brainly.com/question/6007181

#SPJ4

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3 If methane burns in a poor supply of air it will give carbon
rusak2 [61]

Answer:

2CH4 + 3O2 → 2CO + 4H2O

Explanation:

When methane is burnt in adequate supply of oxygen, then carbon dioxide is produced but when methane is burnt in limited supply of oxygen, then carbon mono-oxide is produced.

The balanced equation for the same is as follows -

2CH4 + 3O2 → 2CO + 4H2O

4 0
3 years ago
What are the three sources of solid waste
gulaghasi [49]

Answer:

The sources of solid waste include residential, commercial, and industrial activities.

Residences and homes where people live are some of the major sources of solid waste. Garbage from these places include food wastes, plastics, paper, glass, leather, cardboard, metals, yard wastes, ashes and special wastes like bulky household items like electronics, tires, batteries, old mattresses and used oil.

4 0
3 years ago
When water was added to a 4.00 gram mixture of potassium oxalate hydrate (molar mass 184.24 g/mol) and calcium hydrate shown bel
Sliva [168]

Answer:

% (COOK)2H2O = 37.826 %

Explanation:

mix: (COOK)2H2O + Ca(OH)2 → CaC2O4 + H2O

∴ mass mix = 4.00 g

∴ mass (CaC2O4)H2O = 1.20 g

∴ Mw (COOK)2H2O = 184.24 g/mol

∴ Mw (CaC2O4)H2O = 146.12 g/mol

∴ r = mol (COOK)2H2O / mol (CaC2O4)H2O = 1

  • % (COOK)2H2O = (mass (COOK)2H2O / mass Mix) × 100

⇒ mass (COOK)2H2O = (1.20 g (CaC2O4)H2O)×(mol (CaC2O4)H2O / 146.12 g (CaC2O4)H2O)×(mol (COOK)2H2O/mol (CaC2O4)H2O)×(184.24 g (COOK)2H2O/mol (COOK)2H2O)

⇒ mass (COOK)2H2O = 1.513 g

⇒ % (COOK)2H2O = ( 1.513 g / 4 g )×100

⇒ % (COOK)2H2O = 37.826 %

7 0
4 years ago
0.07 mol sample of octane, C^6H^18 absorbed 3.5 x 10^3 J of energy. Calculate the temp increase of octane if the molar heat capa
Dovator [93]

n = number of moles of sample of octane = 0.07 mol

Q = energy absorbed by a sample of octane = 3.5 x 10³ J

c = molar heat capacity of octane = 254.0 J/K* mol

ΔT = increase in temperature of octane = ?

Heat absorbed is given as

Q = n c ΔT

inserting the values

3.5 x 10³ J = (0.07 mol) (254.0 J/K* mol) ΔT

ΔT = (3.5 x 10³ )/((0.07) (254.0))

ΔT = 196.85 K

hence increase in temperature comes out to be 196.85 K


8 0
3 years ago
Magnesium has three naturally occurring isotopes with masses of 23.99 amuamu, 24.99 amuamu, and 25.98 amuamu and natural abundan
bonufazy [111]

Answer:

24.309 g/mol

Explanation:

To get the atomic mass, all we have to do is calculate with the masses of the three isotope, the real quantity present, taking account of the percent and then, do a sum of these three values. Like a pondered media.

For the first isotope:

23.99 * (78.99/100) = 18.95 g/mol

For the second isotope:

24.99 * (10/100) = 2.499 g/mol

For the last isotope:

25.98 * (11.01/100) = 2.86 g/mol

Now, let's sum all three together

AW = 18.95 + 2.499 + 2.86

AW = 24.309 g/mol

3 0
4 years ago
Read 2 more answers
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