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REY [17]
3 years ago
14

A 0.050 kg toy truck moving right at 0.20 m/s collided with a toy car weighing 0.015 kg initially at rest, on a frictionless tra

ck. The truck keeps moving right at 0.15 m/s after the collision,
what is the final speed of the race car?
Physics
2 answers:
Kamila [148]3 years ago
7 0

Answer:

0.1667 m/s

Explanation:

m1V1 + m2V2 = m1V3 + m2V4

0.01 = ( 0.0075) + (0.015 * V4)

V4 = (0.01 - 0.0075) / (0.015)

V4= 0.1667

Arada [10]3 years ago
6 0

Answer:

0.167 m/s

Explanation:

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2 years ago
An electron is released a short distance above earth's surface. a second electron directly below it exerts an electrostatic forc
slamgirl [31]

The mass of an electron is 9.109 x 10⁻³¹ kg

The weight of the electron is (mass) x (g) =  8.926 x 10⁻³⁰ Newton

The charge on an electron is -1.602 x 10⁻¹⁹ Coulomb

The repelling force between the two electrons is (K · q₁ · q₂ / r²) =

(8.98755 x 10⁹ N-m²/C²) x (1.602 x 10⁻¹⁹ C)² / D²

In order for the bottom one to just exactly hold the top one up at a distance 'D', the repelling force has to be exactly equal to the weight of the upper electron.

8.926 x 10⁻³⁰ N = (8.98755 x 10⁹ N-m²/C²)·(1.602 x 10⁻¹⁹ C)² / D²

We have to solve THAT ugly mess for ' D '.

Clean up the units first:

Cancel the C² on the right side, then divide each side by Newton:

8.926 x 10⁻³⁰ = (8.98755 x 10⁹ m²) x (1.602 x 10⁻¹⁹)² / D²

Now, let's multiply both sides by (D² x 10²⁹) :

D² x 8.926 x 10⁻¹ = (8.98755 m²) x (1.602)²

Divide each side by (0.8926):

D² = (8.98755 x 1.602²) / (0.8926)  meter²

D² = 25.84 m²

Take the square root of each side:

<em>D = 5.08 meters</em>

I am shocked, impressed, and amazed !

Are you shocked, impressed, or amazed ?

3 0
4 years ago
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