Answer:
As velocity is uniform then acceleration will be zero.
Explanation:
From the diagram we have that



Therefore the direction is 30° from east of south
Answer:
(a) 
(b) 
(c) 
Explanation:
Given that,
(a) An electron accelerated from rest through a potential difference of 100 V. The De Broglie wavelength in terms of potential difference is given by :

Where
m and e are the mass of and charge on an electron
On solving,

V = 100 V


(b) V = 1 kV = 1000 V



(c) If 


Hence, this is the required solution.
I would go with Segment D.
Answer:
(B) tightly packed protons and neutrons
Explanation:
- Nucleus of any atom is the dense central part of any atom.
- It consists of two sub-atomic particle namely proton and neutron.
- These sub-atomic parts are tightly packed in nucleus which makes the nucleus dense .
- This dense nucleus is responsible for most of the mass of atom.
- The atomic mass for any atom is decided by sum of the mass of proton and neutron
Thus, correct answer is
(B) tightly packed protons and neutrons