Oh your from the other question you made I just saw it LOL. 
But heres the answer click the 3 dots on the question you made or you can ask a Moderator or Administrator to remove your question with a reason.
        
                    
             
        
        
        
Answer:
i think it's 2km pm
Explanation:
2km x 30 60.. start was 30, and now your at 90.. we had to determine how much time it took.. so 2 is the average.. or atleast per minute and sorry it i still didnt answer ur question lol im just trynna help
 
        
             
        
        
        
Answer:
4.5g/cm^3
Explanation:
Here, Mass(m)=67.5g
          Volume(v)=15cm^3
Now, According to formula,
         Density(p)=m/v
                          =67.5/15
                          =4.5g/cm^3
 
        
             
        
        
        
Answer:
  F = 7.68 10¹¹ N,  θ = 45º
Explanation:
In this exercise we ask for the net electric force. Let's start by writing the configuration of the charges, the charges of the same sign must be on the diagonal of the cube so that the net force is directed towards the interior of the cube, see in the attached numbering and sign of the charges
The net force is
           F_ {net} = F₂₁ + F₂₃ + F₂₄
bold letters indicate vectors. The easiest method to solve this exercise is by using the components of each force.
let's use trigonometry
           cos 45 = F₂₄ₓ / F₂₄
           sin 45 = F_{24y) / F₂₄
           F₂₄ₓ = F₂₄ cos 45
           F_{24y} = F₂₄ sin 45
let's do the sum on each axis
X axis
           Fₓ = -F₂₁ + F₂₄ₓ
           Fₓ = -F₂₁₁ + F₂₄ cos 45
Y axis  
          F_y = - F₂₃ + F_{24y}
          F_y = -F₂₃ + F₂₄ sin 45
They indicate that the magnitude of all charges is the same, therefore
          F₂₁ = F₂₃
Let's use Coulomb's law
          F₂₁ = k q₁ q₂ / r₁₂²
         
the distance between the two charges is
          r = a
          F₂₁ = k q² / a²
we calculate F₂₄
            F₂₄ = k q₂ q₄ / r₂₄²
the distance is
            r² = a² + a²
            r² = 2 a²
          
we substitute
            F₂₄ = k  q² / 2 a²
we substitute in the components of the forces
           Fx =  
           Fx =  ( -1 + ½ cos 45)
  ( -1 + ½ cos 45)
           F_y = k \frac{q^2}{a^2} ( -1 +  ½ sin 45)    
          
We calculate
             F₀ = 9 10⁹ 4.25² / 0.440²
             F₀ = 8.40 10¹¹ N
        
             Fₓ = 8.40 10¹¹ (½ 0.707 - 1)
             Fₓ = -5.43 10¹¹ N
          
remember cos 45 = sin 45
              F_y = - 5.43 10¹¹  N
We can give the resultant force in two ways
 a) F = Fₓ î + F_y ^j
           F = -5.43 10¹¹ (i + j)   N
b) In the form of module and angle.
For the module we use the Pythagorean theorem
           F =  
           F = 5.43 10¹¹  √2
           F = 7.68 10¹¹ N
in angle is
            θ = 45º
 
        
             
        
        
        
Answer:
ok confusion but we could figure it out right 
Explanation:
<h3>dhdjhdndnd but its fine how was your day tho </h3>