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nasty-shy [4]
1 year ago
9

The positron created in pair production travels a certain distance and loses all of its kinetic energy. It finally annihilates w

ith an electron and releases two photons. What is the angular separation between the two photons
Physics
1 answer:
hichkok12 [17]1 year ago
7 0

Answer:

In pair production, after the loss of Kinetic energy, the angular separation between the two photons is 180°.

Explanation:

  • Pair production is the process of formation of two electrons, one negative and the other positive (positron), from a pulse of electromagnetic energy traveling through matter.

  • It is a process of direct conversion of radiant energy to matter.

  • The sum of the Kinetic energies of the formed particles amounts to a value of 4 MeV.

  • When the kinetic energy is lost, emission of two photons, each with an energy of approximately 1 MeV in the form of gamma rays takes place ( in opposite direction).

Therefore, the angle of separation between the two photons is 180°.

Learn more about electromagnetic energy here:

<u>brainly.com/question/9221254</u>

#SPJ4

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Answer:

\lambda'=78.086\ nm

Explanation:

Given:

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<u>Now we have the relation for time:</u>

\rm time=\frac{distance}{speed}

hence,

t=\frac{d}{c}

c= speed of light in air

16.7\times 10^{-9}=\frac{d}{3\times 10^8}

d=16.7\times 10^{-9}\times 3\times 10^8

d=5.01\ m

For the case when glass slab is inserted between the path of light:

\frac{(d-x)}{c} +\frac{x}{v} =t' (since light travel with the speed c only in the air)

here:

v = speed of light in the glass

\frac{(5.01-0.87)}{3\times 10^8} +\frac{0.87}{v} =21.3\times 10^{-9}

v=4.42\times 10^7\ m.s^{-1}

Using Snell's law:

\frac{\lambda}{\lambda'} =\frac{c}{v}

\frac{530}{\lambda'} =\frac{3\times 10^8}{4.42\times 10^7}

\lambda'=78.086\ nm

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Explanation :

Given that,

A track begins at 0 meters and has a total distance of 100 meters. Juliet starts at the 10-meter mark while practicing for a race.

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So, the correct option is (D) " 55 meters ".

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