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Free_Kalibri [48]
3 years ago
13

Which points are the verticles of the ellipse? Equations of ellipse

Mathematics
1 answer:
Mashutka [201]3 years ago
3 0

Answer:

This question is solved in detail below. Please refer to the attachment for better understanding of an Ellipse.

Step-by-step explanation:

In this question, there is a spelling mistake. This is vertices not verticles.

So, I have attached a diagram of an ellipse in which it is clearly mentioned where are the vertices of an ellipse.

Vertices of an Ellipse: There are two axes in any ellipse, one is called major axis and other is called minor axis. Where, minor is the shorter axis and major axis is the longer one. The places or points where major axis and minor axis ends are called the vertices of an ellipse. Please refer to the attachment for further clarification.

Equations of an ellipse in its standard form:

\frac{x^{2} }{a^{2} }  + \frac{y^{2} }{b^{2} } = 1

This is the case when major axis the longer one is on the x-axis centered at an origin.

\frac{x^{2} }{b^{2} } + \frac{y^{2} }{a^{2} }  = 1

This is the case when major axis the longer one is on the y-axis centered at an origin.

where major axis length = 2a

and minor axis length = 2b

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Answer:

y = 2x - 5

Step-by-step explanation:

Using the slope intercept formula y2 - y1 / x2 -x1...

You get a slope of 2 so y = 2x +b

Then to find b the intercept, you plug in one of the coordinates like so...

1 = 2(3) + b

Then solve to get an intercept of -5.

So the slope-intercept form would be...

y = 2x - 5

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In the expression 3x + 5x – 3y + 5, which terms are “like terms”?
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Step-by-step explanation: 3x and 5x both have x

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Draw the line with equation x+y=2
DanielleElmas [232]

Answer:

Arrange the variables to y intercept form: y=-x+2. We have the slope is -1, and the y intercept is 2. You should be able to draw a line from here.

Step-by-step explanation:

6 0
3 years ago
A man hits a baseball when it is 4 ft above the ground with an initial velocity of 120 ft/sec. The ball leaves the bat at a 30 d
Sauron [17]
<span>et us assume that the origin is the floor right below the 30 ft. fence

To work this one out, we'll start with acceleration and integrate our way up to position.

At the time that the player hits the ball, the only force in action is gravity where: a = g (vector)
ax = 0
ay = -g (let's assume that g = 32.8 ft/s^2. If you use a different value for gravity, change the numbers.

To get the velocity of the ball, we integrate the acceleration
vx = v0x = v0cos30 = 103.92
vy = -gt + v0y = -32.8t + v0sin40 = -32.8t + 60

To get the positioning, we integrate the speed.
x = v0cos30t + x0 = 103.92t - 350
y = 1/2*(-32.8)t² + v0sin30t + y0 = -16.4t² + 60t + 4

If the ball clears the fence, it means x = 0, y > 30

x = 0 -> 103.92 t - 350 = 0 -> t = 3.36 seconds

for t = 3.36s,
y = -16.4(3.36)^2 + 60*(3.36) + 4
= 20.45 ft

which is less than 30ft, so it means that the ball will NOT clear the fence.


Just for fun, let's check what the speed should have been :)

x = v0cos30t + x0 = v0cos30t - 350
y = 1/2*(-32.8)t² + v0sin30t + y0 = -16.4t² + v0sin30t + 4

x = 0 -> v0t = 350/cos30
y = 30 ->
-16.4t^2 + v0t(sin30) + 4 = 30
-16.4t^2 + 350sin30/cos30 = 26
t^2 = (26 - 350tan30)/-16.4
t = 3.2s

v0t = 350/cos30 -> v0 = 350/tcos30 = 123.34 ft/s

So he needed to hit the ball at at least 123.34 ft/s to clear the fence.

You're welcome, Thanks please :)
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Solve the system of equations given below
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Answer:

idek

Step-by-step explanation:

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