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allsm [11]
3 years ago
7

☆☆10 points☆☆BRAINLIEST IF CORRECT ANSWER!​

Mathematics
1 answer:
zavuch27 [327]3 years ago
6 0

Answer:

this \: paper \: needs \: to \: be \: folded \:  \\  \underline{ \boxed{twice \: (2 \: times)}}

Step-by-step explanation:

let \: the \: let \: the \: length \: be \to \: x \\when \: folded :  it \: becomes \to \:  \frac{x}{2}  \\hence : \to \\  93.5 \times  \frac{x}{2}  = (93.5 - 1) \\ 93.5x = 2(93.5 - 1) \\ 93.5x = 2 \times 92.5 \\ 93.5x = 185 \\ x =  \frac{185}{93.5}  \\  \boxed{x = 1.9786096257 }\\

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To the nearest whole number, what is the mean number of letters per word in this sentence?
sertanlavr [38]
I counted 72 letters and 17 words so...
72/17 = 4.23 to the nearest whole number: 4 letters per word
5 0
3 years ago
Please help me !??!!!
iris [78.8K]

Answer:

X =0

Step-by-step explanation:

divide each term by 15 and simp

4 0
2 years ago
Find the surface area of the composite figure. 6cm 5 cm 20cm 4cm 12cm 6cm​
Crazy boy [7]

Answer:

644 cm²

Step-by-step explanation:

Surface area of the composite figure = surface area of the large rectangular prism + surface area of the small rectangular prism - 2(area of the surface of the small rectangular prism that joins the larger prism)

✔️Surface area of the large rectangular prism = 2(LW + LH + WH)

L = 6 cm

W = 5 cm

H = 20 cm

Surface area = 2(6*5 + 6*20 + 5*20)

= 500 cm²

✔️Surface area of the small rectangular prism = 2(LW + LH + WH)

L = 6 cm

W = 4 cm

H = 12 cm

Surface area = 2(6*4 + 6*12 + 4*12)

= 288 cm²

✔️area of the surface of the small rectangular prism that joins the larger prism = L*W

L = 12 cm

W = 6 cm

Area = 12*6

= 72 cm²

✅Surface area of the composite figure = 500 + 288 - 2(72)

= 644 cm²

7 0
3 years ago
-2(9 + 3n) - 9 (1 - 10n)*
GuDViN [60]

Answer:

-27+84n

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
1. Write an equation in slope-intercept form for a line passing through (-3,3) with a slope of 1.
PIT_PIT [208]

1)


\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{3})~\hspace{10em} slope = m\implies 1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-3=1[x-(-3)] \\\\\\ y-3=1(x+3)\implies y-3=x+3\implies y=x+6


2)


\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{12}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{12-2}{1-(-4)}\implies \cfrac{10}{1+4}\implies \cfrac{10}{5}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=2[x-(-4)]\implies y-2=2(x+4) \\\\\\ y-2=2x+8\implies y=2x+10

8 0
3 years ago
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