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3 years ago

Find the value of two numbers if their sum is 17 and their difference is 3.

Mathematics

1 answer:

AVprozaik [17]3 years ago

4 0

Step-by-step explanation:

x+y=17 (First equation)

x-y=3 (Second equation)

Solving Equation (i)

x+y=17

x=17-y(First equation)

Putting value of x in equation (ii)

x-y=3

x=3+y

17-y=3+y

17=3+y+y

17=3+2y

2y=17-3

y=14/2

y=7

Putting value of y in equation(i)

x=17-y

x=17-7

x=10

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Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8

Delvig [45]

We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51$

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98$

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34$
Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86$

Thus the 98% confidence interval will be (105.34, 141.86)

Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.

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4 years ago

5. Carlotta's Beauty Supply store sells two brands of bar soap. A 6 pack of Brand A costs

vekshin1

I think it would be be because you’re actually saving a little bit more amount of money you’re paying a dollar and would say two cent for each bar

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3 years ago

Your teacher asked you to represent 3 more than 8 multiplied by a number t as an expression. You wrote 3 + 8t, and your friend w

Leni [432]

Both answers are not the same. You are correct and your friend is wrong. The situation your teacher gave could have only one other interpretation that would be acceptable and that would be 8t+3 because it is the same number just in a different order.

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3 years ago

Write the expression in its written form. 3/8×(1−13)

kaheart [24]

Answer:

7 /8

0.875

Step-by-step explanation:

4 0

3 years ago

What are the points if the slope is 4 and the point is (1,-1)

kherson [118]

The points if the slope is 4 and the point is (1,-1) are (1,-1) and (2, 3)

<h3>What are linear equations?</h3>

Linear equations are equations that have constant average rates of change, slope or gradient

<h3>How to determine the points?</h3>

The given parameters are:

Slope = 4

Point = (1, -1)

The slope of 4 means that as x changes by 1, the value of y changes by 4

This means that, we have:

(x + 1, y + 4)

Substitute the known values in the above equation

(1 + 1, -1 + 4)

Evaluate

(2, 3)

Hence, the points if the slope is 4 and the point is (1,-1) are (1,-1) and (2, 3)

Read more about linear equations at:

brainly.com/question/14323743

#SPJ1

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2 years ago