Round 12.5829 to the nearest tenth.

0.64 x 0.81 help im on a time limit ಥ_ಥ

lorasvet [3.4K]

Answer:

0.5184

Step-by-step explanation:

hope this helps!!!

8 0

3 years ago

Read 2 more answers

A map has a scale of 3 in. = 16 mi. If you measured the distance between two cities to be 23 in. on the map, how many miles woul

Scrat [10]

Answer:

122.667

Step-by-step explanation:

23/3=7.667

7.667*16=122.667

8 0

3 years ago

Please help. I’ll mark you as brainliest if correct!

chubhunter [2.5K]

Answer:

$\boxed{\sf \ \ \ f^{-1}(x)=1+\sqrt{x} \ \ \ }$

Step-by-step explanation:

the minimum of f is for x = 1 and f(1)=0

f is decreasing for x<=1 and increasing for x>=1

so the domain is $[1;+\infty[$

$f^{-1}(f(x))=x =f^{-1}((x-1)^2)\\\\f(f^{-1}(x))=x=(f^{-1}(x)-1)^2$

x>=1 so x is positive and we can take the square root

so $f^{-1}(x)=1+\sqrt{x}$

8 0

3 years ago

Can you help me please??

dusya [7]

Answer:

y = $\frac{4}{5}x+\frac{54}{5}$

Step-by-step explanation:

Equation of a line has been given as,

$y=\frac{4}{5}x+\frac{3}{5}$

Here, slope of the line = $\frac{4}{5}$

y-intercept = $\frac{3}{5}$

"If the two lines are parallel, there slopes will be equal"

By this property slope of the parallel line to the given line will be equal.

Therefore, slope 'm' = $\frac{4}{5}$

Since, slope intercept form of a line is,

y = mx + b

Therefore, equation of the parallel line will be,

y = $\frac{4}{5}x+b$

Since, this line passes through a point (-6, 6),

6 = $\frac{4}{5}(-6)+b$

6 = $-\frac{24}{5}+b$

b = $6+\frac{24}{5}$

b = $\frac{30+24}{5}$

b = $\frac{54}{5}$

Equation of the parallel line will be,

y = $\frac{4}{5}x+\frac{54}{5}$

4 0

3 years ago

Please help with the question in the picture!

Stella [2.4K]

Answer:

Tan C = 3/4

Step-by-step explanation:

Given-

∠ A = 90°, sin C = 3 / 5

METHOD - I

Sin² C + Cos² C = 1

Cos² C = 1 - Sin² C

Cos² C = $1 - \frac{9}{25}$

Cos² C = $\frac{25 - 9}{25}$

Cos² C = $\frac{16}{25}$

Cos C = $\sqrt{\frac{16}{25} }$

Cos C = $\frac{4}{5}$

As we know that

Tan C = $\frac{Sin C}{Cos C }$

Tan C = $\frac{\frac{3}{5} }{\frac{4}{5} }$

Tan C = $\frac{3}{4}$ 

METHOD - II

Given Sin C = $\frac{3}{5} = \frac{Height}{Hypotenuse}$

therefore,

AB ( Height ) = 3; BC ( Hypotenuse) = 5

∵ ΔABC is Right triangle.

∴ By Pythagorean Theorem-

AB² + AC² = BC²

AC² = BC² - AB²

AC² = 5² - 3²

AC² = 25 - 9

AC² = 16

AC ( Base) = 4

Since,

Tan C = $\frac{Height}{Base}$ 

Tan C = $\frac{AB}{AC}$

Hence Tan C = $\frac{3}{4}$ 

4 0

3 years ago