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2 years ago

Round 12.5829 to the nearest tenth.

Mathematics

1 answer:

Vikentia [17]2 years ago

3 0

the answer is 12.6 :)

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What is the arc measure of BDC in degrees?<br> (4k + 159)<br> P<br> (2k + 153)

andre [41]

<h2>Explanation:</h2><h2></h2>

The diagram is missing but I'll assume that the arc BDC is:

$(4k + 159)^{\circ}$

And another arc, let's call it FGH. measures:

$(2k + 153)^{\circ}$

If those arc are equal, then this equation is true:

$(4k + 159)^{\circ}=(2k + 153)^{\circ} \\ \\ (4k + 159)=(2k + 153) \\ \\ \\ Solving \ for \ k: \\ \\ 4k-2k=153-159 \\ \\ 2k=-6 \\ \\ k=-\frac{6}{2} \\ \\ k=-3$

Substituting k into the first equation:

$\angle BDC=(4(-3)+159)^{\circ} \\ \\ \angle BDC=(-12+159)^{\circ} \\ \\ \boxed{\angle BDC=147^{\circ}}$

3 0

3 years ago

Read 2 more answers

In Mr. Siegel’s class, 15% of the students are in the Scrapbooking Club and 45% are in the Cooking Club. His remaining students

Oksanka [162]

Answer:

Step-by-step explanation:

15% = 15/100= 0.15

45% = 45/100 = o.45

Remaining students: 40% = 40/100 = 0.4%

6 0

2 years ago

the width of a rectangle is 9m less than it's legnth if the perimeter of the rectangle is 54m find the legnth of the garden

Nata [24]

Perimeter of rectangle = 2(l+w)

So, 54cm = 2(l+9cm)

=> 54cm = 2l + 18cm

=> 54cm - 18cm = 2l

=> 36cm = 2l

=> 36cm/2 = l

=> 18cm = l

4 0

2 years ago

The width of a rectangle is increasing at a rate of 2 cm/sec, while the length increases at 3 cm/sec. At what rate is the area i

lorasvet [3.4K]

Answer:

The area of the rectangle is increasing at a rate of $22\ cm^2/s$ .

Step-by-step explanation:

Given : The width of a rectangle is increasing at a rate of 2 cm/ sec. While the length increases at 3 cm/sec.

To find : At what rate is the area increasing when w = 4 cm and I = 5 cm?

Solution :

The area of the rectangle with length 'l' and width 'w' is given by $A=l w$

Derivative w.r.t 't',

$\frac{dA}{dt}=w\frac{dl}{dt}+l\frac{dw}{dt}$

Now, we have given

$\frac{dl}{dt}=3\ cm/s$

$l=5\ cm$

$\frac{dw}{dt}=2\ cm/s$

$w=4\ cm$

Substitute all the values,

$\frac{dA}{dt}=(4)(3)+(5)(2)$

$\frac{dA}{dt}=12+10$

$\frac{dA}{dt}=22\ cm^2/s$

Therefore, the area of the rectangle is increasing at a rate of $22\ cm^2/s$ .

4 0

3 years ago

Can someone please help me answer my question

algol [13]

The surface area would be 150cm and the volume would be 125cm. To get volume you do 5 cubed to get the answer 125. To get surface area you would do 5 multiplied by 5 multiplied by the cubes 6 sides to get 150.

4 0

3 years ago

Read 2 more answers