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Lorico [155]
3 years ago
7

Find the difference between the result of one sixth of product of 10 and 3 multiplied by 4 and 30

Mathematics
1 answer:
kherson [118]3 years ago
6 0

Answer:

10 or -10,

Read the explanation

Step-by-step explanation:

Rewrite this problem as a numerical expression. As per the wording of this problem, there can be two expressions derived.

1.     ((\frac{1}{6}(10*3)*4)-30

2.     30-((\frac{1}{6}(10*3)*4)

Simplify, remember the order of operations. The order of operations is the sequence by which one is supposed to perform operations in a numerical expression. This order is the following:

1. Parenthesis

2. Exponents

3. Multiplication or division

4. Addition or Subtraction

Use this sequence when simplifying and solving the expression:

Expression 1

((\frac{1}{6}(10*3)*4)-30\\\\=((\frac{1}{6}(30)*4)-30\\\\=(5*4)-30\\\\=20 - 30\\\\= -10

Expression 2

30-((\frac{1}{6}(10*3)*4)\\\\=30-((\frac{1}{6}(30)*4)\\\\=30-(5*4)\\\\= 30-20\\\\= 10

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Suppose small aircraft arrive at a certain airport according to a Poisson process with rate α = 8 per hour, so that the number o
Ksenya-84 [330]

Answer:

Step-by-step explanation:

Step1:

We have Suppose small aircraft arrive at a certain airport according to a Poisson process with rate α =8 per hour, so that the number of arrivals during a time period of t hours is a Poisson rv with parameter μ = 8t

Step2:

Let “X” the number of small aircraft that arrive during time t and it follows poisson distribution parameter “”

The probability mass function of poisson distribution is given by

P(X) = , x = 0,1,2,3,...,n.

Where, μ(mean of the poisson distribution)

a).

Given that time period t = 1hr.

Then,μ = 8t

             = 8(1)

             = 8

Now,

The probability that exactly 6 small aircraft arrive during a 1-hour period is given by

P(exactly 6 small aircraft arrive during a 1-hour period) = P(X = 6)

Consider,

P(X = 6) =  

              =  

              =  

              = 0.1219.

Therefore,The probability that exactly 6 small aircraft arrive during a 1-hour period is 0.1219.

1).P(At least 6) = P(X 6)

Consider,

P(X 6) = 1 - P(X5)

                = 1 - {+++++}

                = 1 - (){+++++}

                = 1 - (0.000335){+++++}

                = 1 - (0.000335){1+8+32+85.34+170.67+273.07}

                = 1 - (0.000335){570.08}

                = 1 - 0.1909

                = 0.8090.

Therefore, the probability that at least 6 small aircraft arrive during a 1-hour period is 0.8090.

2).P(At least 10) = P(X 10)

Consider,

P(X 10) = 1 - P(X9)

                 = 1 - {+++++

5 0
3 years ago
A watch cost $75.99. If the sales tax rate is 6.25%, what is the amount of sales tax?
Luden [163]

75.99*0.0625=4.75 hope helps

7 0
3 years ago
Find the minimum angle of rotation of the given figure a. 40* b. 60* c. 45* d. 8*
Mila [183]
I’m not an expert at this but my guess is 45 degrees. Can you let me know what the correct answer was?
6 0
3 years ago
Read 2 more answers
What is the first step to solve this equation: 12-4x=54
ValentinkaMS [17]

Answer:

B. subtract 12 from both sides

Step-by-step explanation:

12-4x=54

<u>-12 -12</u>

<u>-</u><u>4</u><u>x</u><u>=</u><u>4</u><u>2</u>

4 0
3 years ago
Read 2 more answers
List five rational numbers between -4/5 and -2/3 . Please tell by step by step explaintion ​
attashe74 [19]

9514 1404 393

Answer:

  -0.67, -0.68, -0.69, -0.70, -0.71

Step-by-step explanation:

There are an infinite number of ways to do this.

Perhaps the simplest is to do it in decimal.

 -4/5 = -0.8

  -2/3 = -0.666... (repeating 6)

Any negative decimal number between these values will do. For example, ...

  -0.67, -0.68, -0.69, -0.70, -0.71

__

If you want to choose fractions that are evenly spaced between the given values, you can find their difference, then divide that difference into 6 parts (1 more than the number of numbers you need).

  -2/3 -(-4/5) = 4/5 -2/3 = (12 -10)/(5·3) = 2/15 . . . . length of interval

  1/6 of this difference is ...

     (1/6)(2/15) = 2/90 = 1/45

The interval end point nearest 0 is ...

  -2/3 = -30/45

so the 5 intermediate values will be that value with -1/45 repeatedly added:

  -31/45, -32/45, -33/45 = -11/15, -34/45, -35/45 = -7/9

_____

<em>Additional comment</em>

The fractions we came up with could be referred to as "5 arithmetic means between -2/3 and -4/5." There is nothing in the problem statement suggesting the values need to be evenly spaced.

When doing this in decimal, you can obtain a new value simply by adding more digits to the decimal fraction:

  -0.68, -0.685, -0.6853, -0.68531, -0.799

7 0
3 years ago
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