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3 years ago

Shown below is a prism.

Mathematics

1 answer:

tigry1 [53]3 years ago

8 0

Answer:

Volume = 126 cm^2

Step-by-step explanation:

You don't exactly know what the base looks like, but it doesn't matter. The volume of a Prism is Base * height.

Solution

V = Base (which is the Cross sectional Area) * Length

V = 21 cm^2 * 6 cm

V = 126 cm^2

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Use complete sentences to describe the relationship between sets A and B if A ⊆ B.

asambeis [7]

Answer:

b includes a in it this is a full sentense

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3 years ago

Katherine and Crystal do landscaping. They recently earned $1472 for a project. If Katherine earned $5 for every $3 earned by Cr

Degger [83]

Answer:

Katherine: 920

Crystal: 552

Step-by-step explanation:

The total amount earned by each is 1472

The ratio of the earnings is Katherine / Crustal = 5/3

The total number of shares = 5 + 3 = 8

So the proportion for Katherine

5/8 = x / 1472 Cross multiply

8x = 5 * 1472

8x = 7360

x = 7360/8

x = 920

And the proportion for Crystal is

3/8 = x / 1472 Cross multiply

8x = 3 * 1472

8x = 4416

x = 4416 / 8

x = 552

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3 years ago

Julio is 36 years old, and James is 11 years old. In how many years will Julio’s age be twice a many as James’s age?

boyakko [2]

Answer:

in 14 years Julio will be 50 and James will be 25

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3 years ago

Please anythign would be helpful fast ill mark brainliest

saveliy_v [14]

I believe it is 180° around H and translate 2 up 5 right

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3 years ago

Sally Sue had spent all day preparing for the prom. All the glitz and the glamour of the evening fell apart as she stepped out o

Nuetrik [128]

We have the function

$p(t)=550(1-e^{-0.039t})$

Therefore we want to determine when we have

$p(t_0)=550$

It means that the term

$e^{-0.039t}$

Must go to zero, then let's forget the rest of the function for a sec and focus only on this term

$e^{-0.039t}\rightarrow0$

But for which value of t? When we have a decreasing exponential, it's interesting to input values that are multiples of the exponential coefficient, if we have 0.039 in the exponential, let's define that

$\alpha=\frac{1}{0.039}$

The inverse of the number, but why do that? look what happens when we do t = α

$e^{-0.039t}\Rightarrow e^{-0.039\alpha}\Rightarrow e^{-1}=\frac{1}{e}$

And when t = 2α

$e^{-0.039t}\Rightarrow e^{-0.039\cdot2\alpha}\Rightarrow e^{-2}=\frac{1}{e^2}$

We can write it in terms of e only.

And we can find for which value of α we have a small value that satisfies

$e^{-0.039t}\approx0$

Only using powers of e

Let's write some inverse powers of e:

$\begin{gathered} \frac{1}{e}=0.368 \\ \\ \frac{1}{e^2}=0.135 \\ \\ \frac{1}{e^3}=0.05 \\ \\ \frac{1}{e^4}=0.02 \\ \\ \frac{1}{e^5}=0.006 \end{gathered}$

See that at t = 5α we have a small value already, then if we input p(5α) we can get

$\begin{gathered} p(5\alpha)=550(1-e^{-0.039\cdot5\alpha}) \\ \\ p(5\alpha)=550(1-0.006) \\ \\ p(5\alpha)=550(1-0.006) \\ \\ p(5\alpha)=550\cdot0.994 \\ \\ p(5\alpha)\approx547 \end{gathered}$

That's already very close to 550, if we want a better approximation we can use t = 8α, which will result in 549.81, which is basically 550.

Therefore, we can use t = 5α and say that 3 people are not important for our case, and say that it's basically 550, or use t = 8α and get a very close value.

In both cases, the decimal answers would be

$\begin{gathered} 5\alpha=\frac{5}{0.039}=128.2\text{ minutes (good approx)} \\ \\ 8\alpha=\frac{8}{0.039}=205.13\text{ minutes (even better approx)} \end{gathered}$

7 0

1 year ago