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balu736 [363]
3 years ago
14

Graph the function. y = -2x + 5

Mathematics
1 answer:
algol133 years ago
7 0
It’s shown in the picture !!!!!!

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Help me please *for brainliest*!!!
Amiraneli [1.4K]
B. 18.37

1990 - 1960 = 30 = t

Plug in the variable "t" to the equation and solve.

P (t) = 18.37
6 0
3 years ago
What is 5✓28 +✓63 In simplest radical form<br>I need it asap.
Ksenya-84 [330]

Answer:

13✓7

Step-by-step explanation:

5✓28 + ✓63

Break the radical into perfect squares.


5 times ✓4 times ✓7  +  ✓9 times ✓7

5 times 2 times ✓7  +  3 ✓7


10✓7 + 3✓7


13✓7

5 0
3 years ago
Which statement is true of z11.7?
Alexxx [7]

Answer

z11.7 is between 1 and 2 standard deviations of the mean.

Step-by-step explanation:

7 0
3 years ago
I need help with this ASAP please!!
Ilia_Sergeevich [38]

Answer:

Translation 1 unit left

Step-by-step explanation:

we have

f(x)=x

g(x)=(x+1)

we know that

The rule of the transformation of f(x) to g(x) is equal to

f(x) ------> g(x)

(x,y) -----> (x-1,y)

That means----> The translation is 1 unit to the left

6 0
3 years ago
A woman is randomly selected from the 18–24 age group. For women of this group, systolic blood pressures (in mm Hg) are normally
Naddik [55]

Answer:

X \sim N(114.8,13.1)  

Where \mu=114.8 and \sigma=13.1

We are interested on this probability

P(X>140)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

And we can find this probability using the complement rule:

P(z>1.924)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(114.8,13.1)  

Where \mu=114.8 and \sigma=13.1

We are interested on this probability

P(X>140)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:P(X>140)=P(\frac{X-\mu}{\sigma}>\frac{140-\mu}{\sigma})=P(Z>\frac{140- 1114.8}{2.6})=P(z>1.924)And we can find this probability using the complement rule:

P(z>1.924)=1-P(z

8 0
4 years ago
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