The equation will be of the form:
![A(t)= A_{0} e^{rt}](https://tex.z-dn.net/?f=A%28t%29%3D%20A_%7B0%7D%20e%5E%7Brt%7D)
where A is the amount after t hours, and r is the decay constant.
To find the value of r, we plug the given values into the equation, giving:
![40=320e^{3r}](https://tex.z-dn.net/?f=40%3D320e%5E%7B3r%7D)
Rearranging and taking natural logs of both sides, we get:
![ln\ 0.125=3r](https://tex.z-dn.net/?f=ln%5C%200.125%3D3r)
![r=\frac{ln\ 0.125}{3}=-0.693](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Bln%5C%200.125%7D%7B3%7D%3D-0.693)
The required model is:
<span>my answer for B is 28.84
hope I could help
</span>
Answer:
14 x 0.27 = 3.78 is your answer
Explanation:
the question is asking for the weight of the object so you multiply and get 3.79
Area of a rectangle: A = 24 a² b
Length: L = 8 a b²
Width: W = A / L = 24 a² b / 8 a b²
Answer: W = 3 a / b