there is no triangle drawn
Answer:
Bucket 2
Step-by-step explanation:
Bucket 1 = 4700ml
Bucket 2 = 4.8l
Bucket 3 = 3880ml
Bucket 4 = 4.71 l
Convert holding capacity of bucket 1 and bucket 3 into liters
1 liter = 1000 milliliter
Bucket 1 = 4700ml
4700ml = 4.7l
Bucket 3 = 3880ml
3880ml = 3.88l
Therefore,
Bucket 1 = 4.7l
Bucket 2 = 4.8l
Bucket 3 = 3.88l
Bucket 4 = 4.71 l
The bucket closest to 5liters is bucket 2 with a holding capacity of 4.8 liters
Step-by-step explanation:
Domain of a rational function is everywhere except where we set vertical asymptotes. or removable discontinues
Here, we have
First, notice we have x in both the numerator and denomiator so we have a removable discounties at x.
Since, we don't want x to be 0,
We have a removable discontinuity at x=0
Now, we have
We don't want the denomiator be zero because we can't divide by zero.
so
So our domain is
All Real Numbers except-2 and 0.
The vertical asymptors is x=-2.
To find the horinzontal asymptote, notice how the numerator and denomator have the same degree. So this mean we will have a horinzontal asymptoe of
The leading coeffixent of the numerator/ the leading coefficent of the denomiator.
So that becomes
So we have a horinzontal asymptofe of 2
Given : f(x)= 3|x-2| -5
f(x) is translated 3 units down and 4 units to the left
If any function is translated down then we subtract the units at the end
If any function is translated left then we add the units with x inside the absolute sign
f(x)= 3|x-2| -5
f(x) is translated 3 units down
subtract 3 at the end, so f(x) becomes
f(x)= 3|x-2| -5 -3
f(x) is translated 4 units to the left
Add 4 with x inside the absolute sign, f(x) becomes
f(x)= 3|x-2 + 4| -5 -3
We simplify it and replace f(x) by g(x)
g(x) = 3|x + 2| - 8
a= 3, h = -2 , k = -8
